OCR MEI C4 2015 June — Question 4 8 marks

Exam BoardOCR MEI
ModuleC4 (Core Mathematics 4)
Year2015
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeFind maximum or minimum value
DifficultyModerate -0.3 This is a standard harmonic form question requiring routine application of the R cos(x - α) transformation formula and solving R = √(1 + λ²) = 2. The method is well-practiced in C4, involving straightforward algebraic manipulation with no novel insight required, making it slightly easier than average.
Spec1.05l Double angle formulae: and compound angle formulae1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc

4 You are given that \(\mathrm { f } ( x ) = \cos x + \lambda \sin x\) where \(\lambda\) is a positive constant.
  1. Express \(\mathrm { f } ( x )\) in the form \(R \cos ( x - \alpha )\), where \(R > 0\) and \(0 < \alpha < \frac { 1 } { 2 } \pi\), giving \(R\) and \(\alpha\) in terms of \(\lambda\).
  2. Given that the maximum value (as \(x\) varies) of \(\mathrm { f } ( x )\) is 2 , find \(R , \lambda\) and \(\alpha\), giving your answers in exact form.

Question 4: [2 marks]
Explanation of how 188 seconds derived from 8 stops calculation
**Question 4:** [2 marks]
Explanation of how 188 seconds derived from 8 stops calculation
4 You are given that $\mathrm { f } ( x ) = \cos x + \lambda \sin x$ where $\lambda$ is a positive constant.\\
(i) Express $\mathrm { f } ( x )$ in the form $R \cos ( x - \alpha )$, where $R > 0$ and $0 < \alpha < \frac { 1 } { 2 } \pi$, giving $R$ and $\alpha$ in terms of $\lambda$.\\
(ii) Given that the maximum value (as $x$ varies) of $\mathrm { f } ( x )$ is 2 , find $R , \lambda$ and $\alpha$, giving your answers in exact form.

\hfill \mbox{\textit{OCR MEI C4 2015 Q4 [8]}}