OCR MEI C4 2015 June — Question 3 8 marks

Exam BoardOCR MEI
ModuleC4 (Core Mathematics 4)
Year2015
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGeneralised Binomial Theorem
TypeMultiply by polynomial
DifficultyStandard +0.3 This is a straightforward application of the binomial expansion for negative/fractional powers followed by polynomial multiplication. Part (i) requires routine use of the formula (1+x)^n with n=-1/3, and stating the validity condition |2x|<1 is standard. Part (ii) involves multiplying the expansion by (1-3x) and collecting terms, which is mechanical algebra. Slightly above average difficulty due to the fractional power and two-part structure, but no novel insight required.
Spec1.04c Extend binomial expansion: rational n, |x|<11.04d Binomial expansion validity: convergence conditions

3
  1. Find the first three terms of the binomial expansion of \(\frac { 1 } { \sqrt [ 3 ] { 1 - 2 x } }\). State the set of values of \(x\) for which
    the expansion is valid. the expansion is valid.
  2. Hence find \(a\) and \(b\) such that \(\frac { 1 - 3 x } { \sqrt [ 3 ] { 1 - 2 x } } = 1 + a x + b x ^ { 2 } + \ldots\).

Question 3: [2 marks]
Apply expression from line 51 with n=10 upper floors, p=7 people, answer to 2 d.p.
**Question 3:** [2 marks]
Apply expression from line 51 with n=10 upper floors, p=7 people, answer to 2 d.p.
3 (i) Find the first three terms of the binomial expansion of $\frac { 1 } { \sqrt [ 3 ] { 1 - 2 x } }$. State the set of values of $x$ for which\\
the expansion is valid. the expansion is valid.\\
(ii) Hence find $a$ and $b$ such that $\frac { 1 - 3 x } { \sqrt [ 3 ] { 1 - 2 x } } = 1 + a x + b x ^ { 2 } + \ldots$.

\hfill \mbox{\textit{OCR MEI C4 2015 Q3 [8]}}