OCR MEI C4 2011 January — Question 6 8 marks

Exam BoardOCR MEI
ModuleC4 (Core Mathematics 4)
Year2011
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Lines & Planes
TypeLine intersection with plane
DifficultyStandard +0.3 This is a straightforward application of standard vector methods: substituting the line equation into the plane equation to find λ, then using the dot product formula for angles. Both parts are routine textbook exercises requiring no problem-solving insight, though slightly above average difficulty due to being a two-part question involving coordinate manipulation.
Spec4.04a Line equations: 2D and 3D, cartesian and vector forms4.04c Scalar product: calculate and use for angles4.04f Line-plane intersection: find point

6
  1. Find the point of intersection of the line \(\mathbf { r } = \left( \begin{array} { r } - 8 \\ - 2 \\ 6 \end{array} \right) + \lambda \left( \begin{array} { r } - 3 \\ 0 \\ 1 \end{array} \right)\) and the plane \(2 x - 3 y + z = 11\).
  2. Find the acute angle between the line and the normal to the plane. Section B (36 marks)

6 (i) Find the point of intersection of the line $\mathbf { r } = \left( \begin{array} { r } - 8 \\ - 2 \\ 6 \end{array} \right) + \lambda \left( \begin{array} { r } - 3 \\ 0 \\ 1 \end{array} \right)$ and the plane $2 x - 3 y + z = 11$.\\
(ii) Find the acute angle between the line and the normal to the plane.

Section B (36 marks)\\

\hfill \mbox{\textit{OCR MEI C4 2011 Q6 [8]}}