OCR MEI C4 2010 January — Question 2 1 marks

Exam BoardOCR MEI
ModuleC4 (Core Mathematics 4)
Year2010
SessionJanuary
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeProve identity then solve equation
DifficultyStandard +0.3 This is a straightforward two-part question: proving a standard double angle identity using known formulae (cot 2θ = cos 2θ/sin 2θ, then applying tan forms) followed by a routine algebraic equation. The proof requires recall of double angle formulae and basic manipulation. The equation solving involves substituting the identity, clearing fractions, and solving a quadratic in tan θ—all standard C4 techniques with no novel insight required. Slightly above average difficulty due to the two-part structure and algebraic manipulation, but well within typical C4 scope.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

2 Show that \(\cot 2 \theta = \frac { 1 - \tan ^ { 2 } \theta } { 2 \tan \theta }\).
Hence solve the equation $$\cot 2 \theta = 1 + \tan \theta \quad \text { for } 0 ^ { \circ } < \theta < 360 ^ { \circ }$$

Question 2:
AnswerMarks Guidance
AnswerMarks Guidance
THE MATHEMATICIANB1
### Question 2:
| Answer | Marks | Guidance |
|--------|-------|----------|
| THE MATHEMATICIAN | B1 | |
2 Show that $\cot 2 \theta = \frac { 1 - \tan ^ { 2 } \theta } { 2 \tan \theta }$.\\
Hence solve the equation

$$\cot 2 \theta = 1 + \tan \theta \quad \text { for } 0 ^ { \circ } < \theta < 360 ^ { \circ }$$

\hfill \mbox{\textit{OCR MEI C4 2010 Q2 [1]}}