OCR C4 2015 June — Question 5 6 marks

Exam BoardOCR
ModuleC4 (Core Mathematics 4)
Year2015
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration by Substitution
TypeSubstitution with exponential functions
DifficultyStandard +0.3 This is a straightforward substitution question where the substitution is explicitly given. Students must find dt/dx, rearrange to express dx in terms of dt, substitute into the integral, and integrate e^(2t). While it requires careful algebraic manipulation and understanding of the substitution method, it follows a standard template with no conceptual surprises, making it slightly easier than average.
Spec1.08h Integration by substitution

5 By first using the substitution \(t = \sqrt { x + 1 }\), find \(\int \mathrm { e } ^ { 2 \sqrt { x + 1 } } \mathrm {~d} x\).

Question 5:
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{dt}{dx}=k(x+1)^{-1/2}\) or \(\frac{dx}{dt}=2t\) from \(x=t^2\pm1\) oeM1 Or e.g. \(k\,dt=\frac{dx}{\sqrt{x+1}}\) oe
\(\int kte^{2t}\,dt\)M1* \(k\) is any non-zero constant
\(kt\times\frac{1}{2}e^{2t}\pm k\int\frac{1}{2}e^{2t}\,dt\)M1dep*
\(te^{2t}-\int e^{2t}\,dt\)A1 May be implied by the next A1
\(te^{2t}-\frac{1}{2}e^{2t}\)A1
\(\sqrt{x+1}\,e^{2\sqrt{x+1}}-\frac{1}{2}e^{2\sqrt{x+1}}+c\) cao wwwA1 \(+c\) may be seen in previous line only for A1; if \(dt\) not seen in integral at some point impose penalty of 1 mark from total mark of 2 or more
# Question 5:
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{dt}{dx}=k(x+1)^{-1/2}$ or $\frac{dx}{dt}=2t$ from $x=t^2\pm1$ oe | M1 | Or e.g. $k\,dt=\frac{dx}{\sqrt{x+1}}$ oe |
| $\int kte^{2t}\,dt$ | M1* | $k$ is any non-zero constant |
| $kt\times\frac{1}{2}e^{2t}\pm k\int\frac{1}{2}e^{2t}\,dt$ | M1dep* | |
| $te^{2t}-\int e^{2t}\,dt$ | A1 | May be implied by the next A1 |
| $te^{2t}-\frac{1}{2}e^{2t}$ | A1 | |
| $\sqrt{x+1}\,e^{2\sqrt{x+1}}-\frac{1}{2}e^{2\sqrt{x+1}}+c$ cao www | A1 | $+c$ may be seen in previous line only for **A1**; if $dt$ not seen in integral at some point impose penalty of 1 mark from total mark of 2 or more |

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5 By first using the substitution $t = \sqrt { x + 1 }$, find $\int \mathrm { e } ^ { 2 \sqrt { x + 1 } } \mathrm {~d} x$.

\hfill \mbox{\textit{OCR C4 2015 Q5 [6]}}