OCR C4 2015 June — Question 3 6 marks

Exam BoardOCR
ModuleC4 (Core Mathematics 4)
Year2015
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferentiating Transcendental Functions
TypeFind stationary points - mixed transcendental products
DifficultyStandard +0.3 This requires product rule differentiation of exponential and trigonometric functions, then solving a transcendental equation for stationary points. While it involves multiple techniques (product rule, setting derivative to zero, solving tan x = -2), these are standard C4 procedures with no novel insight required. The numerical solving aspect and restricted domain make it slightly above average difficulty but still routine for this level.
Spec1.07q Product and quotient rules: differentiation

3 The equation of a curve is \(y = \mathrm { e } ^ { 2 x } \cos x\). Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) and hence find the coordinates of any stationary points for which \(- \pi \leqslant x \leqslant \pi\). Give your answers correct to 3 significant figures.

Question 3:
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{dy}{dx}=\pm ke^{2x}\cos x \pm e^{2x}\sin x\)M1* \(k\) is any constant; Product Rule
\(\frac{dy}{dx}=2e^{2x}\cos x - e^{2x}\sin x\) oeA1
Their \(\frac{dy}{dx}=0\)M1dep*
\(\tan x=2\) or \(\cos x=(\pm)\frac{1}{\sqrt{5}}\) or \(\sin x=(\pm)\frac{2}{\sqrt{5}}\)A1 Ignore omission of "\(e^{2x}=0\) has no solution"; or \(\sqrt{5}\cos(x+\tan^{-1}\frac{1}{2})=0\)
\(x=1.11\) and \(-2.03\) caoA1 \((1.11, 4.09)\) and/or \((-2.03,-0.00765)\); if A0A0, SC1 for all 4 values to greater precision
\(y=4.09\) and \(-0.00765\) caoA1 Or A1 for each correct pair of coordinates; extra values within range incur penalty of one mark
# Question 3:
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{dy}{dx}=\pm ke^{2x}\cos x \pm e^{2x}\sin x$ | M1* | $k$ is any constant; Product Rule |
| $\frac{dy}{dx}=2e^{2x}\cos x - e^{2x}\sin x$ oe | A1 | |
| Their $\frac{dy}{dx}=0$ | M1dep* | |
| $\tan x=2$ or $\cos x=(\pm)\frac{1}{\sqrt{5}}$ or $\sin x=(\pm)\frac{2}{\sqrt{5}}$ | A1 | Ignore omission of "$e^{2x}=0$ has no solution"; or $\sqrt{5}\cos(x+\tan^{-1}\frac{1}{2})=0$ |
| $x=1.11$ and $-2.03$ cao | A1 | $(1.11, 4.09)$ and/or $(-2.03,-0.00765)$; if **A0A0**, **SC1** for all 4 values to greater precision |
| $y=4.09$ and $-0.00765$ cao | A1 | Or **A1** for each correct pair of coordinates; extra values within range incur penalty of one mark |

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3 The equation of a curve is $y = \mathrm { e } ^ { 2 x } \cos x$. Find $\frac { \mathrm { d } y } { \mathrm {~d} x }$ and hence find the coordinates of any stationary points for which $- \pi \leqslant x \leqslant \pi$. Give your answers correct to 3 significant figures.

\hfill \mbox{\textit{OCR C4 2015 Q3 [6]}}