OCR C4 2012 June — Question 9 9 marks

Exam BoardOCR
ModuleC4 (Core Mathematics 4)
Year2012
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPartial Fractions
TypeRepeated linear factor with distinct linear factor – decompose and integrate
DifficultyStandard +0.3 This is a standard C4 partial fractions question with a repeated linear factor, followed by routine integration. Part (i) requires the standard technique for decomposing with repeated factors, and part (ii) involves straightforward integration of logarithmic and algebraic terms. While it requires careful algebraic manipulation and multiple steps, it follows a well-practiced procedure with no novel insight needed, making it slightly easier than average.
Spec1.02y Partial fractions: decompose rational functions1.08j Integration using partial fractions

9
  1. Express \(\frac { x ^ { 2 } - x - 11 } { ( x + 1 ) ( x - 2 ) ^ { 2 } }\) in partial fractions.
  2. Find the exact value of \(\int _ { 3 } ^ { 4 } \frac { x ^ { 2 } - x - 11 } { ( x + 1 ) ( x - 2 ) ^ { 2 } } \mathrm {~d} x\), giving your answer in the form \(a + \ln b\), where \(a\) and \(b\) are rational numbers.

Question 9:
Part (i):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{A}{x+1} + \frac{B}{x-2} + \frac{C}{(x-2)^2}\)B1 Correct partial fractions format
\(A(x-2)^2 + B(x+1)(x-2) + C(x+1) = x^2 - x - 11\)M1 Equivalent identity or method
\(A = -1\)A1 B1 if cover-up method used
\(B = 2\)A1
\(C = -3\)A1 B1 if cover-up method used
Special Cases:
- \(\frac{A}{x+1} + \frac{Bx+C}{(x-2)^2}\): allow B1 for PF format, M1 for identity, B1 for \(A=-1\) (max 3)
- \(\frac{A}{x+1} + \frac{B}{x-2} + \frac{Cx+D}{(x-2)^2}\): allow B1 for PF format, M1 for identity, B1 for \(A=-1\) (max 3)
- \(\frac{A}{x+1} + \frac{Bx}{(x-2)^2}\): allow B0 for PF format, M1 for identity (max 1, even if \(A=-1\))
- \(\frac{A}{x+1} + \frac{B}{(x-2)^2}\): allow B0 for PF format, M1 for identity (max 1, even if \(A=-1\))
Part (ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(\int \frac{\lambda}{x+1}\, dx = \left(\lambda \text{ or } \frac{1}{\lambda}\right)\ln(x+1)\)B1 \(\int \frac{\lambda}{x-2}\, dx = \left(\lambda \text{ or } \frac{1}{\lambda}\right)\ln(x-2)\)
\(\int \frac{\mu}{(x-2)^2}\, dx = -\left(\mu \text{ or } \frac{1}{\mu}\right)\frac{1}{x-2}\)B1
\(-\frac{3}{2}\)B1 ft ft \(\frac{C}{2}\)
\(\cdots + \ln\frac{16}{5}\) (ISW for either term)B1 ft ft \(\cdots + \ln\left\{\left(\frac{5}{4}\right)^A \cdot 2^B\right\}\)
## Question 9:

### Part (i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{A}{x+1} + \frac{B}{x-2} + \frac{C}{(x-2)^2}$ | B1 | Correct partial fractions format |
| $A(x-2)^2 + B(x+1)(x-2) + C(x+1) = x^2 - x - 11$ | M1 | Equivalent identity or method |
| $A = -1$ | A1 | B1 if cover-up method used |
| $B = 2$ | A1 | |
| $C = -3$ | A1 | B1 if cover-up method used |

**Special Cases:**
- $\frac{A}{x+1} + \frac{Bx+C}{(x-2)^2}$: allow B1 for PF format, M1 for identity, B1 for $A=-1$ (max 3)
- $\frac{A}{x+1} + \frac{B}{x-2} + \frac{Cx+D}{(x-2)^2}$: allow B1 for PF format, M1 for identity, B1 for $A=-1$ (max 3)
- $\frac{A}{x+1} + \frac{Bx}{(x-2)^2}$: allow B0 for PF format, M1 for identity (max 1, even if $A=-1$)
- $\frac{A}{x+1} + \frac{B}{(x-2)^2}$: allow B0 for PF format, M1 for identity (max 1, even if $A=-1$)

### Part (ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\int \frac{\lambda}{x+1}\, dx = \left(\lambda \text{ or } \frac{1}{\lambda}\right)\ln(x+1)$ | B1 | $\int \frac{\lambda}{x-2}\, dx = \left(\lambda \text{ or } \frac{1}{\lambda}\right)\ln(x-2)$ |
| $\int \frac{\mu}{(x-2)^2}\, dx = -\left(\mu \text{ or } \frac{1}{\mu}\right)\frac{1}{x-2}$ | B1 | |
| $-\frac{3}{2}$ | B1 ft | ft $\frac{C}{2}$ |
| $\cdots + \ln\frac{16}{5}$ (ISW for either term) | B1 ft | ft $\cdots + \ln\left\{\left(\frac{5}{4}\right)^A \cdot 2^B\right\}$ |

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9 (i) Express $\frac { x ^ { 2 } - x - 11 } { ( x + 1 ) ( x - 2 ) ^ { 2 } }$ in partial fractions.\\
(ii) Find the exact value of $\int _ { 3 } ^ { 4 } \frac { x ^ { 2 } - x - 11 } { ( x + 1 ) ( x - 2 ) ^ { 2 } } \mathrm {~d} x$, giving your answer in the form $a + \ln b$, where $a$ and $b$ are rational numbers.

\hfill \mbox{\textit{OCR C4 2012 Q9 [9]}}