OCR C4 2012 June — Question 1 6 marks

Exam BoardOCR
ModuleC4 (Core Mathematics 4)
Year2012
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPartial Fractions
TypeSimplify algebraic fractions by addition or subtraction
DifficultyModerate -0.8 This is a straightforward algebraic manipulation question requiring factorization and combining fractions over a common denominator. Part (i) is simple factorization and cancellation; part (ii) is routine fraction subtraction with no conceptual difficulty. Both are standard textbook exercises requiring only mechanical algebraic skills, making this easier than average for A-level.
Spec1.02k Simplify rational expressions: factorising, cancelling, algebraic division

1 Simplify
  1. \(\frac { 1 - x } { x ^ { 2 } - 3 x + 2 }\),
  2. \(\frac { ( x + 1 ) } { ( x - 1 ) ( x - 3 ) } - \frac { ( x - 5 ) } { ( x - 3 ) ( x - 4 ) }\).

Question 1:
Part (i)
AnswerMarks Guidance
AnswerMarks Guidance
\(x^2 - 3x + 2 = (x-1)(x-2)\) or \((1-x)(2-x)\)B1
Obtain \(-\frac{1}{x-2}\) or \(\frac{1}{2-x}\) or \(\frac{-1}{x-2}\) or \(\frac{1}{-(x-2)}\)B1 Not \(\frac{-1}{-(2-x)}\); Accept WW
Total: [2]
Part (ii)
AnswerMarks Guidance
AnswerMarks Guidance
Attempt single fraction or 2 fractions with same relevant denominatorM1 e.g. \((x-1)(x-4)[(x-3)\) or \((x-3)^2]\)
Fully correct fraction(s) before any simplificationA1
Relevant numerator \(= 3x - 9\) or \(3x^2 - 18x + 27\)B1 Can award if no denominator
Final answer \(= \frac{3}{(x-1)(x-4)}\) or \(\frac{3}{x^2-5x+4}\)A1
Total: [4]
S.R. If partial fractions used: \(-\frac{1}{x-1}+\frac{2}{x-3}\)(M1)(A1)
\(\frac{2}{x-3}-\frac{1}{x-4}\)(A1)
\(-\frac{1}{x-1}+\frac{1}{x-4}\) ISW(A1)
# Question 1:

## Part (i)
| Answer | Marks | Guidance |
|--------|-------|----------|
| $x^2 - 3x + 2 = (x-1)(x-2)$ or $(1-x)(2-x)$ | B1 | |
| Obtain $-\frac{1}{x-2}$ or $\frac{1}{2-x}$ or $\frac{-1}{x-2}$ or $\frac{1}{-(x-2)}$ | B1 | Not $\frac{-1}{-(2-x)}$; Accept WW |
| **Total: [2]** | | |

## Part (ii)
| Answer | Marks | Guidance |
|--------|-------|----------|
| Attempt single fraction or 2 fractions with same relevant denominator | M1 | e.g. $(x-1)(x-4)[(x-3)$ or $(x-3)^2]$ |
| Fully correct fraction(s) before any simplification | A1 | |
| Relevant numerator $= 3x - 9$ or $3x^2 - 18x + 27$ | B1 | Can award if no denominator |
| Final answer $= \frac{3}{(x-1)(x-4)}$ or $\frac{3}{x^2-5x+4}$ | A1 | |
| **Total: [4]** | | |
| S.R. If partial fractions used: $-\frac{1}{x-1}+\frac{2}{x-3}$ | (M1)(A1) | |
| $\frac{2}{x-3}-\frac{1}{x-4}$ | (A1) | |
| $-\frac{1}{x-1}+\frac{1}{x-4}$ ISW | (A1) | |

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1 Simplify\\
(i) $\frac { 1 - x } { x ^ { 2 } - 3 x + 2 }$,\\
(ii) $\frac { ( x + 1 ) } { ( x - 1 ) ( x - 3 ) } - \frac { ( x - 5 ) } { ( x - 3 ) ( x - 4 ) }$.

\hfill \mbox{\textit{OCR C4 2012 Q1 [6]}}