OCR C4 2012 June — Question 8 10 marks

Exam BoardOCR
ModuleC4 (Core Mathematics 4)
Year2012
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicImplicit equations and differentiation
TypeFind dy/dx at a point
DifficultyModerate -0.3 Part (a) is a straightforward implicit differentiation exercise requiring product rule and collecting terms, then substituting a point. Parts (b)(i) and (b)(ii) are standard parametric differentiation applications testing dx/dt = 0 and dx/dt = dy/dt respectively. All techniques are routine C4 content with no novel problem-solving required, making this slightly easier than average.
Spec1.07s Parametric and implicit differentiation

8
  1. Find the gradient of the curve \(x ^ { 2 } + x y + y ^ { 2 } = 3\) at the point \(( - 1 , - 1 )\).
  2. A curve \(C\) has parametric equations $$x = 2 t ^ { 2 } - 1 , y = t ^ { 3 } + t$$
    1. Find the coordinates of the point on \(C\) at which the tangent is parallel to the \(y\)-axis.
    2. Find the values of \(t\) for which \(x\) and \(y\) have the same rate of change with respect to \(t\).

Question 8:
Part (a)
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{d}{dx}(xy) = x\frac{dy}{dx}+y\)B1
\(\frac{d}{dx}(y^2) = 2y\frac{dy}{dx}\)B1
Substitute \((-1,-1)\) for \((x,y)\) and attempt to solve for \(\frac{dy}{dx}\)M1 or solve then substitute
Obtain \(\frac{dy}{dx} = -1\) WWWA1
Total: [4]
Part (b)(i)
AnswerMarks Guidance
AnswerMarks Guidance
Tangent parallel to \(y\)-axis \(\to \frac{dx}{dt}=0\) or \(\frac{dy}{dx}\to\infty\) or \(\frac{dy}{dx}=\infty\)M1 Accept clear intention
Obtain \(t=0\)A1
\((-1, 0)\) with no other possibilitiesA1 Accept \(x=-1\), \(y=0\)
Total: [3]
Part (b)(ii)
AnswerMarks Guidance
AnswerMarks Guidance
State or imply or use \(\frac{dy}{dt} = \frac{dx}{dt}\)M1
Produce \(3t^2+1=4t\) oeA1
\(t=\frac{1}{3}\) or \(1\)A1
Total: [3]
# Question 8:

## Part (a)
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{d}{dx}(xy) = x\frac{dy}{dx}+y$ | B1 | |
| $\frac{d}{dx}(y^2) = 2y\frac{dy}{dx}$ | B1 | |
| Substitute $(-1,-1)$ for $(x,y)$ and attempt to solve for $\frac{dy}{dx}$ | M1 | or solve then substitute |
| Obtain $\frac{dy}{dx} = -1$ WWW | A1 | |
| **Total: [4]** | | |

## Part (b)(i)
| Answer | Marks | Guidance |
|--------|-------|----------|
| Tangent parallel to $y$-axis $\to \frac{dx}{dt}=0$ or $\frac{dy}{dx}\to\infty$ or $\frac{dy}{dx}=\infty$ | M1 | Accept clear intention |
| Obtain $t=0$ | A1 | |
| $(-1, 0)$ with no other possibilities | A1 | Accept $x=-1$, $y=0$ |
| **Total: [3]** | | |

## Part (b)(ii)
| Answer | Marks | Guidance |
|--------|-------|----------|
| State or imply or use $\frac{dy}{dt} = \frac{dx}{dt}$ | M1 | |
| Produce $3t^2+1=4t$ oe | A1 | |
| $t=\frac{1}{3}$ or $1$ | A1 | |
| **Total: [3]** | | |
8
\begin{enumerate}[label=(\alph*)]
\item Find the gradient of the curve $x ^ { 2 } + x y + y ^ { 2 } = 3$ at the point $( - 1 , - 1 )$.
\item A curve $C$ has parametric equations

$$x = 2 t ^ { 2 } - 1 , y = t ^ { 3 } + t$$
\begin{enumerate}[label=(\roman*)]
\item Find the coordinates of the point on $C$ at which the tangent is parallel to the $y$-axis.
\item Find the values of $t$ for which $x$ and $y$ have the same rate of change with respect to $t$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{OCR C4 2012 Q8 [10]}}