OCR MEI C3 2015 June — Question 1 6 marks

Exam BoardOCR MEI
ModuleC3 (Core Mathematics 3)
Year2015
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferentiating Transcendental Functions
TypeFind stationary points - mixed transcendental products
DifficultyStandard +0.3 This is a straightforward application of the product rule to find stationary points of e^(2x)cos(x). Students must differentiate using product and chain rules, set the derivative to zero, and solve a simple trigonometric equation (tan x = 2). While it involves transcendental functions, it's a standard textbook exercise with no novel insight required, making it slightly easier than average.
Spec1.07j Differentiate exponentials: e^(kx) and a^(kx)1.07k Differentiate trig: sin(kx), cos(kx), tan(kx)1.07n Stationary points: find maxima, minima using derivatives

1 Fig. 1 shows part of the curve \(y = \mathrm { e } ^ { 2 x } \cos x\). \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{955bebfb-04a3-4cd9-a33e-a8ba4b73e2ba-2_670_1029_404_504} \captionsetup{labelformat=empty} \caption{Fig. 1}
\end{figure} Find the coordinates of the turning point P .

AnswerMarks Guidance
\(y = e^{2x}\cos x\)M1 product rule used
\(\Rightarrow \frac{dy}{dx} = 2e^{2x}\cos x - e^{2x}\sin x\)A1 cao – mark final ans
\(\frac{dy}{dx} = 0 \Rightarrow e^{2x}(2\cos x - \sin x) = 0\)M1 their derivative = 0
\(\Rightarrow 2\cos x = \sin x\)M1 sin x / cos x = tan x used
\(\Rightarrow 2 = \sin x/\cos x = \tan x\)A1 1.1 or 0.35π or better, or arctan 2, not 63.4°; but condone ans given in both degrees and radians here
\(\Rightarrow y = 4.09\)A1 cao art 4.1
Total: [6] consistent with their derivs e.g. 2e^{2x} - e^{2x}tan x is A0; no choice; 1.1071487 …, 0.352416…π, penalise incorrect rounding
$y = e^{2x}\cos x$ | M1 | product rule used
$\Rightarrow \frac{dy}{dx} = 2e^{2x}\cos x - e^{2x}\sin x$ | A1 | cao – mark final ans
$\frac{dy}{dx} = 0 \Rightarrow e^{2x}(2\cos x - \sin x) = 0$ | M1 | their derivative = 0
$\Rightarrow 2\cos x = \sin x$ | M1 | sin x / cos x = tan x used
$\Rightarrow 2 = \sin x/\cos x = \tan x$ | A1 | 1.1 or 0.35π or better, or arctan 2, not 63.4°; but condone ans given in both degrees and radians here
$\Rightarrow y = 4.09$ | A1 cao | art 4.1

**Total: [6]** | | consistent with their derivs e.g. 2e^{2x} - e^{2x}tan x is A0; no choice; 1.1071487 …, 0.352416…π, penalise incorrect rounding

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1 Fig. 1 shows part of the curve $y = \mathrm { e } ^ { 2 x } \cos x$.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{955bebfb-04a3-4cd9-a33e-a8ba4b73e2ba-2_670_1029_404_504}
\captionsetup{labelformat=empty}
\caption{Fig. 1}
\end{center}
\end{figure}

Find the coordinates of the turning point P .

\hfill \mbox{\textit{OCR MEI C3 2015 Q1 [6]}}