OCR C3 2009 January — Question 6 9 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2009
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeFind intersection points
DifficultyStandard +0.3 This is a straightforward multi-part question on inverse functions requiring standard techniques: finding an inverse algebraically, applying the reflection property y=x, and using a given iteration formula. All steps are routine C3 material with no novel problem-solving required, making it slightly easier than average.
Spec1.02v Inverse and composite functions: graphs and conditions for existence1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

6 \includegraphics[max width=\textwidth, alt={}, center]{c940af95-e291-402a-856c-9090d13163d5-3_627_689_264_726} The function f is defined for all real values of \(x\) by $$f ( x ) = \sqrt [ 3 ] { \frac { 1 } { 2 } x + 2 }$$ The graphs of \(y = \mathrm { f } ( x )\) and \(y = \mathrm { f } ^ { - 1 } ( x )\) meet at the point \(P\), and the graph of \(y = \mathrm { f } ^ { - 1 } ( x )\) meets the \(x\)-axis at \(Q\) (see diagram).
  1. Find an expression for \(\mathrm { f } ^ { - 1 } ( x )\) and determine the \(x\)-coordinate of the point \(Q\).
  2. State how the graphs of \(y = \mathrm { f } ( x )\) and \(y = \mathrm { f } ^ { - 1 } ( x )\) are related geometrically, and hence show that the \(x\)-coordinate of the point \(P\) is the root of the equation $$x = \sqrt [ 3 ] { \frac { 1 } { 2 } x + 2 }$$
  3. Use an iterative process, based on the equation \(x = \sqrt [ 3 ] { \frac { 1 } { 2 } x + 2 }\), to find the \(x\)-coordinate of \(P\), giving your answer correct to 2 decimal places.

Question 6:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Attempt correct process for finding inverseM1 maybe in terms of \(y\) so far
Obtain \(2x^3 - 4\)A1 or equiv; in terms of \(x\) now
State \(\sqrt[3]{2}\) or 1.26B1 3
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
State reflection in \(y = x\)B1 or clear equiv
Refer to intersection of \(y = x\) and \(y = f(x)\) and hence confirm \(x = \sqrt[3]{\frac{1}{2}x + 2}\)B1 2
Part (iii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Obtain correct first iterateB1
Show correct process for iterationM1 with at least one more step
Obtain at least 3 correct iterates in allA1 allowing recovery after error
Obtain 1.39A1 4
Iterates shown: \([0 \to 1.259921 \to 1.380330 \to 1.390784 \to 1.391684\), \(1 \to 1.357209 \to 1.388789 \to 1.391512 \to 1.391747\), \(1.26 \to 1.380337 \to 1.390784 \to 1.391684 \to 1.391761\), \(1.5 \to 1.401020 \to 1.392564 \to 1.391837 \to 1.391775\), \(2 \to 1.442250 \to 1.396099 \to 1.392141 \to 1.391801]\)
# Question 6:

## Part (i):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Attempt correct process for finding inverse | M1 | maybe in terms of $y$ so far |
| Obtain $2x^3 - 4$ | A1 | or equiv; in terms of $x$ now |
| State $\sqrt[3]{2}$ or 1.26 | B1 | **3** | |

## Part (ii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| State reflection in $y = x$ | B1 | or clear equiv |
| Refer to intersection of $y = x$ and $y = f(x)$ and hence confirm $x = \sqrt[3]{\frac{1}{2}x + 2}$ | B1 | **2** | AG; or equiv |

## Part (iii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Obtain correct first iterate | B1 | |
| Show correct process for iteration | M1 | with at least one more step |
| Obtain at least 3 correct iterates in all | A1 | allowing recovery after error |
| Obtain 1.39 | A1 | **4** | following at least 3 steps; answer required to exactly 2 d.p. |

Iterates shown: $[0 \to 1.259921 \to 1.380330 \to 1.390784 \to 1.391684$, $1 \to 1.357209 \to 1.388789 \to 1.391512 \to 1.391747$, $1.26 \to 1.380337 \to 1.390784 \to 1.391684 \to 1.391761$, $1.5 \to 1.401020 \to 1.392564 \to 1.391837 \to 1.391775$, $2 \to 1.442250 \to 1.396099 \to 1.392141 \to 1.391801]$

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6\\
\includegraphics[max width=\textwidth, alt={}, center]{c940af95-e291-402a-856c-9090d13163d5-3_627_689_264_726}

The function f is defined for all real values of $x$ by

$$f ( x ) = \sqrt [ 3 ] { \frac { 1 } { 2 } x + 2 }$$

The graphs of $y = \mathrm { f } ( x )$ and $y = \mathrm { f } ^ { - 1 } ( x )$ meet at the point $P$, and the graph of $y = \mathrm { f } ^ { - 1 } ( x )$ meets the $x$-axis at $Q$ (see diagram).\\
(i) Find an expression for $\mathrm { f } ^ { - 1 } ( x )$ and determine the $x$-coordinate of the point $Q$.\\
(ii) State how the graphs of $y = \mathrm { f } ( x )$ and $y = \mathrm { f } ^ { - 1 } ( x )$ are related geometrically, and hence show that the $x$-coordinate of the point $P$ is the root of the equation

$$x = \sqrt [ 3 ] { \frac { 1 } { 2 } x + 2 }$$

(iii) Use an iterative process, based on the equation $x = \sqrt [ 3 ] { \frac { 1 } { 2 } x + 2 }$, to find the $x$-coordinate of $P$, giving your answer correct to 2 decimal places.

\hfill \mbox{\textit{OCR C3 2009 Q6 [9]}}