| Exam Board | OCR |
|---|---|
| Module | C2 (Core Mathematics 2) |
| Year | 2016 |
| Session | June |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Trig Graphs & Exact Values |
| Type | Find period or state transformations |
| Difficulty | Moderate -0.3 This is a straightforward C2 question on transformations of trig functions. Part (i) is direct recall of the period formula. Part (ii) requires understanding symmetry of sine graphs but uses standard reasoning. Part (iii) involves the tan identity which is a routine technique. All parts are standard textbook exercises with no novel problem-solving required, making it slightly easier than average. |
| Spec | 1.05f Trigonometric function graphs: symmetries and periodicities1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(\frac{2\pi}{a}\) | B1 | State \(\frac{2\pi}{a}\) — any exact equiv; allow in degrees i.e. \(\frac{360}{a}\); B0 if given as a range |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(\frac{1}{5}\pi a = \pi - \frac{2}{5}\pi a\); hence \(a = \frac{5}{6}\) | M1 | Attempt to use symmetry of sine curve, or equiv — allow any correct relationship between two solutions in radians or degrees |
| \(k = \frac{1}{2}\sqrt{3}\) | A1 | Obtain \(a = \frac{5}{6}\) — any exact equiv; CWO |
| A1 | Obtain \(k = \frac{1}{2}\sqrt{3}\) — any exact equiv, not involving sin; A0 if from incorrect \(a\) | |
| Alternative: \(\sin(\frac{4}{5}\pi a) = \sin(\frac{2}{5}\pi a)\); using \(\sin 2A\) identity: \(2\cos(\frac{4}{5}\pi a)=1\), \(a=\frac{5}{6}\), \(k=\frac{1}{2}\sqrt{3}\) | M1, A1, A1 | As far as \(2\cos(\frac{4}{5}\pi a) = 1\) for M1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(\tan(ax) = \sqrt{3}\) | B1 | Allow B1 for correct equation even if no, or incorrect, attempt to solve. Give BOD on notation e.g. \(\frac{\sin}{\cos}(ax)\) as long as correct equation is seen or implied. Allow \(\tan(ax) - \sqrt{3} = 0\) or equiv. Allow B1 for identifying \(ax = \frac{\pi}{3}\) or 60° even if equation in \(\tan(ax)\) not seen – M1 would then be awarded for an attempt at \(x\) |
| Attempt to solve \(\tan(ax) = c\) | M1 | Attempt \(\frac{1}{a}\tan^{-1}(c)\), any non-zero numerical \(c\). M0 for \(\tan^{-1}\left(\frac{c}{a}\right)\). Allow if attempted in degrees not radians. M1 could be implied rather than explicit. M1 can be awarded if using a numerical value for \(a\) |
| \(x = \frac{\pi}{3a}\) | A1 | Must be in radians not degrees. Allow any exact equiv e.g. \(\frac{\pi}{a} \cdot\) as long as intention clear – but A0 if this is then given as \(\frac{a\pi}{3}\) |
| \(x = \frac{4\pi}{3a}\) | A1 | Must be in radians not degrees. Allow any exact equiv e.g. \(\frac{\frac{4\pi}{3}}{a}\) as long as intention clear – but A0 if given as \(\frac{4a\pi}{3}\). Allow \(\frac{\pi}{3a} + \frac{\pi}{a}\) unless then incorrectly simplified. If more than two solutions given, mark the two smallest and ISW the rest. e.g. \(\frac{\pi}{3a}, \frac{4\pi}{3a}, \frac{7\pi}{3a}\) would be A1A1 but \(\frac{\pi}{3a}, \frac{2\pi}{3a}, \frac{4\pi}{3a}\) would be A1A0 |
| [4] |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(\sin^2(ax) = 3\cos^2(ax)\), \(4\sin^2(ax) = 3\) or \(4\cos^2(ax) = 1\), \(\sin(ax) = \pm\frac{\sqrt{3}}{2}\) or \(\cos(ax) = \pm\frac{1}{2}\) | B1 | Any correct, simplified equation in a single trig ratio |
| Attempt to solve \(\sin^2(ax) = c\) or \(\cos^2(ax) = c\) | M1 | Allow M1 if just the positive square root used. Attempt \(\frac{1}{a}\sin^{-1}(\sqrt{c})\) or \(\frac{1}{a}\cos^{-1}(\sqrt{c})\), any non-zero numerical \(c\). M0 for \(\sin^{-1}\left(\frac{\sqrt{c}}{a}\right)\), M0 for \(\cos^{-1}\left(\frac{\sqrt{c}}{a}\right)\). Allow if attempted in degrees not radians. M1 could be implied. M1 can be awarded if using numerical value for \(a\) |
| \(x = \frac{\pi}{3a}\) | A1 | Must be in radians not degrees. Allow any exact equiv as long as intention clear – but A0 if given as \(\frac{a\pi}{3}\) |
| \(x = \frac{4\pi}{3a}\) | A1 | Allow any exact equiv as long as intention clear – but A0 if given as \(\frac{4a\pi}{3}\). Allow a correct answer still in two terms, unless then incorrectly simplified. If more than two solutions given, mark two smallest and ISW the rest. e.g. \(\frac{\pi}{3a}, \frac{4\pi}{3a}, \frac{7\pi}{3a}\) would be A1A1 but \(\frac{\pi}{3a}, \frac{2\pi}{3a}, \frac{4\pi}{3a}\) would be A1A0 |
## Question 9:
### Part (i):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{2\pi}{a}$ | B1 | State $\frac{2\pi}{a}$ — any exact equiv; allow in degrees i.e. $\frac{360}{a}$; B0 if given as a range |
### Part (ii):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{1}{5}\pi a = \pi - \frac{2}{5}\pi a$; hence $a = \frac{5}{6}$ | M1 | Attempt to use symmetry of sine curve, or equiv — allow any correct relationship between two solutions in radians or degrees |
| $k = \frac{1}{2}\sqrt{3}$ | A1 | Obtain $a = \frac{5}{6}$ — any exact equiv; CWO |
| | A1 | Obtain $k = \frac{1}{2}\sqrt{3}$ — any exact equiv, not involving sin; A0 if from incorrect $a$ |
| **Alternative:** $\sin(\frac{4}{5}\pi a) = \sin(\frac{2}{5}\pi a)$; using $\sin 2A$ identity: $2\cos(\frac{4}{5}\pi a)=1$, $a=\frac{5}{6}$, $k=\frac{1}{2}\sqrt{3}$ | M1, A1, A1 | As far as $2\cos(\frac{4}{5}\pi a) = 1$ for M1 |
## Question (iii):
**Main Solution:**
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\tan(ax) = \sqrt{3}$ | B1 | Allow B1 for correct equation even if no, or incorrect, attempt to solve. Give BOD on notation e.g. $\frac{\sin}{\cos}(ax)$ as long as correct equation is seen or implied. Allow $\tan(ax) - \sqrt{3} = 0$ or equiv. Allow B1 for identifying $ax = \frac{\pi}{3}$ or 60° even if equation in $\tan(ax)$ not seen – M1 would then be awarded for an attempt at $x$ |
| Attempt to solve $\tan(ax) = c$ | M1 | Attempt $\frac{1}{a}\tan^{-1}(c)$, any non-zero numerical $c$. M0 for $\tan^{-1}\left(\frac{c}{a}\right)$. Allow if attempted in degrees not radians. M1 could be implied rather than explicit. M1 can be awarded if using a numerical value for $a$ |
| $x = \frac{\pi}{3a}$ | A1 | Must be in radians not degrees. Allow any exact equiv e.g. $\frac{\pi}{a} \cdot$ as long as intention clear – but A0 if this is then given as $\frac{a\pi}{3}$ |
| $x = \frac{4\pi}{3a}$ | A1 | Must be in radians not degrees. Allow any exact equiv e.g. $\frac{\frac{4\pi}{3}}{a}$ as long as intention clear – but A0 if given as $\frac{4a\pi}{3}$. Allow $\frac{\pi}{3a} + \frac{\pi}{a}$ unless then incorrectly simplified. If more than two solutions given, mark the two smallest and ISW the rest. e.g. $\frac{\pi}{3a}, \frac{4\pi}{3a}, \frac{7\pi}{3a}$ would be A1A1 but $\frac{\pi}{3a}, \frac{2\pi}{3a}, \frac{4\pi}{3a}$ would be A1A0 |
| **[4]** | | |
---
**Alternative Solution:**
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\sin^2(ax) = 3\cos^2(ax)$, $4\sin^2(ax) = 3$ or $4\cos^2(ax) = 1$, $\sin(ax) = \pm\frac{\sqrt{3}}{2}$ or $\cos(ax) = \pm\frac{1}{2}$ | B1 | Any correct, simplified equation in a single trig ratio |
| Attempt to solve $\sin^2(ax) = c$ or $\cos^2(ax) = c$ | M1 | Allow M1 if just the positive square root used. Attempt $\frac{1}{a}\sin^{-1}(\sqrt{c})$ or $\frac{1}{a}\cos^{-1}(\sqrt{c})$, any non-zero numerical $c$. M0 for $\sin^{-1}\left(\frac{\sqrt{c}}{a}\right)$, M0 for $\cos^{-1}\left(\frac{\sqrt{c}}{a}\right)$. Allow if attempted in degrees not radians. M1 could be implied. M1 can be awarded if using numerical value for $a$ |
| $x = \frac{\pi}{3a}$ | A1 | Must be in radians not degrees. Allow any exact equiv as long as intention clear – but A0 if given as $\frac{a\pi}{3}$ |
| $x = \frac{4\pi}{3a}$ | A1 | Allow any exact equiv as long as intention clear – but A0 if given as $\frac{4a\pi}{3}$. Allow a correct answer still in two terms, unless then incorrectly simplified. If more than two solutions given, mark two smallest and ISW the rest. e.g. $\frac{\pi}{3a}, \frac{4\pi}{3a}, \frac{7\pi}{3a}$ would be A1A1 but $\frac{\pi}{3a}, \frac{2\pi}{3a}, \frac{4\pi}{3a}$ would be A1A0 |
9 A curve has equation $y = \sin ( a x )$, where $a$ is a positive constant and $x$ is in radians.\\
(i) State the period of $y = \sin ( a x )$, giving your answer in an exact form in terms of $a$.\\
(ii) Given that $x = \frac { 1 } { 5 } \pi$ and $x = \frac { 2 } { 5 } \pi$ are the two smallest positive solutions of $\sin ( a x ) = k$, where $k$ is a positive constant, find the values of $a$ and $k$.\\
(iii) Given instead that $\sin ( a x ) = \sqrt { 3 } \cos ( a x )$, find the two smallest positive solutions for $x$, giving your answers in an exact form in terms of $a$.
\section*{END OF QUESTION PAPER}
\hfill \mbox{\textit{OCR C2 2016 Q9 [8]}}