OCR C2 2016 June — Question 4 6 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Year2016
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLaws of Logarithms
TypeSolve ln equation using subtraction law
DifficultyModerate -0.8 This is a straightforward application of standard logarithm laws (power and subtraction rules) followed by routine algebraic manipulation. Part (i) is pure recall, and part (ii) requires only converting the logarithmic equation to a simple quadratic—well below average difficulty for A-level with no conceptual challenges or problem-solving insight needed.
Spec1.06f Laws of logarithms: addition, subtraction, power rules1.06g Equations with exponentials: solve a^x = b

4
  1. Express \(2 \log _ { 3 } x - \log _ { 3 } ( x + 4 )\) as a single logarithm.
  2. Hence solve the equation \(2 \log _ { 3 } x - \log _ { 3 } ( x + 4 ) = 2\).

Question 4:
Part (i)
AnswerMarks Guidance
AnswerMarks Guidance
\(\log_3 x^2 - \log_3(x+4) = \log_3 \frac{x^2}{x+4}\)B1* Obtain \(\log_3 x^2 - \log_3(x+4)\). Allow no base. Could be implied if both log steps done together. Allow equiv eg \(2(\log_3 x - \log_3(x+4)^{0.5})\)
B1d*Obtain \(\log_3 \frac{x^2}{x+4}\) or equiv single term. CWO so B0 if eg \(\frac{\log x^2}{\log(x+4)}\) seen in solution. No ISW if subsequently incorrectly 'simplified' eg \(\log_3(\frac{x}{4})\). Must now have correct base in final answer
Part (ii)
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{x^2}{x+4} = 3^2\)M1* Attempt correct method to remove logs. Equation must be of form \(\log_3 f(x) = 2\), with \(f(x)\) being the result of a legitimate attempt to combine logs. Allow use of their (i) only if it satisfies the above criteria, so \(x^2 - (x+4) = 9\) is M0 whether or not in (i)
\(x^2 = 9(x+4)\)A1 Obtain any correct equation. Not involving logs
\(x^2 - 9x - 36 = 0\)M1d* Attempt complete method to solve for \(x\). Solving a 3 term quadratic. Must attempt at least one value of \(x\)
\((x-12)(x+3) = 0\)
\(x = 12\)A1 Obtain \(x = 12\) as only solution. Must be from a correct solution of a correct quadratic. A0 if other root (if given) is not \(x = -3\). A0 if \(x = -3\) still present. Not necessary to consider \(x = -3\) and then discard, but A0 if discarded for incorrect reason
# Question 4:

## Part (i)
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\log_3 x^2 - \log_3(x+4) = \log_3 \frac{x^2}{x+4}$ | B1* | Obtain $\log_3 x^2 - \log_3(x+4)$. Allow no base. Could be implied if both log steps done together. Allow equiv eg $2(\log_3 x - \log_3(x+4)^{0.5})$ |
| | B1d* | Obtain $\log_3 \frac{x^2}{x+4}$ or equiv single term. CWO so B0 if eg $\frac{\log x^2}{\log(x+4)}$ seen in solution. No ISW if subsequently incorrectly 'simplified' eg $\log_3(\frac{x}{4})$. Must now have correct base in final answer |

## Part (ii)
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{x^2}{x+4} = 3^2$ | M1* | Attempt correct method to remove logs. Equation must be of form $\log_3 f(x) = 2$, with $f(x)$ being the result of a legitimate attempt to combine logs. Allow use of their (i) only if it satisfies the above criteria, so $x^2 - (x+4) = 9$ is M0 whether or not in (i) |
| $x^2 = 9(x+4)$ | A1 | Obtain any correct equation. Not involving logs |
| $x^2 - 9x - 36 = 0$ | M1d* | Attempt complete method to solve for $x$. Solving a 3 term quadratic. Must attempt at least one value of $x$ |
| $(x-12)(x+3) = 0$ | | |
| $x = 12$ | A1 | Obtain $x = 12$ as only solution. Must be from a correct solution of a correct quadratic. A0 if other root (if given) is not $x = -3$. A0 if $x = -3$ still present. Not necessary to consider $x = -3$ and then discard, but A0 if discarded for incorrect reason |
4 (i) Express $2 \log _ { 3 } x - \log _ { 3 } ( x + 4 )$ as a single logarithm.\\
(ii) Hence solve the equation $2 \log _ { 3 } x - \log _ { 3 } ( x + 4 ) = 2$.

\hfill \mbox{\textit{OCR C2 2016 Q4 [6]}}