OCR C2 2016 June — Question 5 8 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Year2016
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndefinite & Definite Integrals
TypeImproper integral evaluation
DifficultyStandard +0.3 Part (a) requires expanding brackets and integrating polynomials—routine C2 work. Part (b)(i) involves standard integration of negative powers and substituting limits. Part (b)(ii) introduces improper integrals by taking a limit as a→∞, which is slightly beyond typical C2 but follows directly from (b)(i) with minimal additional insight. Overall slightly easier than average due to straightforward techniques.
Spec1.08b Integrate x^n: where n != -1 and sums1.08d Evaluate definite integrals: between limits4.08c Improper integrals: infinite limits or discontinuous integrands

5
  1. Find \(\int \left( x ^ { 2 } + 2 \right) ( 2 x - 3 ) \mathrm { d } x\).
    1. Find, in terms of \(a\), the value of \(\int _ { 1 } ^ { a } \left( 6 x ^ { - 2 } - 4 x ^ { - 3 } \right) \mathrm { d } x\), where \(a\) is a constant greater than 1 .
    2. Deduce the value of \(\int _ { 1 } ^ { \infty } \left( 6 x ^ { - 2 } - 4 x ^ { - 3 } \right) \mathrm { d } x\).

Question 5:
Part (a):
AnswerMarks Guidance
AnswerMarks Guidance
\(\int(2x^3 - 3x^2 + 4x - 6)dx\)M1 Expand brackets and attempt integration; must be reasonable attempt to expand brackets, resulting in at least 3 terms; integration attempt must have increase in power by 1 for at least 3 terms
\(= \frac{1}{2}x^4 - x^3 + 2x^2 - 6x + c\)A1FT Obtain at least three correct (algebraic) terms; allow unsimplified coefficients
A1 [3]Obtain fully correct expression including \(+c\); coefficients must be fully simplified; A0 if integral sign or \(dx\) still present
Part (b)(i):
AnswerMarks Guidance
AnswerMarks Guidance
\(\left[-6x^{-1} + 2x^{-2}\right]^a_1\)M1 Attempt integration; integral must be of form \(k_1x^{-1} + k_2x^{-2}\)
\(= (-6a^{-1} + 2a^{-2}) - (-6 + 2)\)A1 Obtain fully correct expression; allow unsimplified coefficients; allow presence of \(+c\)
\(= 4 - 6a^{-1} + 2a^{-2}\)M1 Attempt correct use of limits; must be \(F(a) - F(1)\); correct order and subtraction
A1 [4]Obtain \(4 - 6a^{-1} + 2a^{-2}\); coefficients simplified and constant terms combined; A0 if \(+c\) present; A0 if integral sign or \(dx\) still present
Part (b)(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(4\)B1FT [1] State 4, following their (i); their (b)(i) must be of form \(k + k_1a^{-1} + k_2a^{-2}\); must appreciate a limit is required; do not allow \(4 + 0\)
# Question 5:

## Part (a):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\int(2x^3 - 3x^2 + 4x - 6)dx$ | M1 | Expand brackets and attempt integration; must be reasonable attempt to expand brackets, resulting in at least 3 terms; integration attempt must have increase in power by 1 for at least 3 terms |
| $= \frac{1}{2}x^4 - x^3 + 2x^2 - 6x + c$ | A1FT | Obtain at least three correct (algebraic) terms; allow unsimplified coefficients |
| | A1 [3] | Obtain fully correct expression including $+c$; coefficients must be fully simplified; A0 if integral sign or $dx$ still present |

## Part (b)(i):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\left[-6x^{-1} + 2x^{-2}\right]^a_1$ | M1 | Attempt integration; integral must be of form $k_1x^{-1} + k_2x^{-2}$ |
| $= (-6a^{-1} + 2a^{-2}) - (-6 + 2)$ | A1 | Obtain fully correct expression; allow unsimplified coefficients; allow presence of $+c$ |
| $= 4 - 6a^{-1} + 2a^{-2}$ | M1 | Attempt correct use of limits; must be $F(a) - F(1)$; correct order and subtraction |
| | A1 [4] | Obtain $4 - 6a^{-1} + 2a^{-2}$; coefficients simplified and constant terms combined; A0 if $+c$ present; A0 if integral sign or $dx$ still present |

## Part (b)(ii):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $4$ | B1FT [1] | State 4, following their (i); their (b)(i) must be of form $k + k_1a^{-1} + k_2a^{-2}$; must appreciate a limit is required; do not allow $4 + 0$ |

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5
\begin{enumerate}[label=(\alph*)]
\item Find $\int \left( x ^ { 2 } + 2 \right) ( 2 x - 3 ) \mathrm { d } x$.
\item \begin{enumerate}[label=(\roman*)]
\item Find, in terms of $a$, the value of $\int _ { 1 } ^ { a } \left( 6 x ^ { - 2 } - 4 x ^ { - 3 } \right) \mathrm { d } x$, where $a$ is a constant greater than 1 .
\item Deduce the value of $\int _ { 1 } ^ { \infty } \left( 6 x ^ { - 2 } - 4 x ^ { - 3 } \right) \mathrm { d } x$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{OCR C2 2016 Q5 [8]}}