| Exam Board | OCR |
|---|---|
| Module | FP3 (Further Pure Mathematics 3) |
| Year | 2009 |
| Session | June |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Vectors: Lines & Planes |
| Type | Line of intersection of planes |
| Difficulty | Standard +0.8 This is a Further Maths question requiring conversion between vector forms of planes and finding line of intersection. Part (i) requires computing a normal vector via cross product, which is routine FP3 technique. Part (ii) requires finding the direction vector (cross product of normals) and a point on both planes (solving simultaneous equations), involving multiple coordinated steps but following standard algorithms. Slightly above average difficulty due to being Further Maths content with computational complexity, but remains a textbook-style exercise. |
| Spec | 4.04b Plane equations: cartesian and vector forms |
| Answer | Marks | Guidance |
|---|---|---|
| \(n_1 = [1, 1, 0] \times [1, -5, -2]\) | M1 | For attempting to find vector product of the pair of direction vectors |
| \(= [-2, 2, -6] = k[1, -1, 3]\) | A1 | For correct \(n_1\) |
| Use \((2, 2, 1)\) | M1 | For substituting a point into equation |
| \(\Rightarrow r \cdot [-2, 2, -6] = -6 \Rightarrow r \cdot [1, -1, 3] = 3\) | A1, 4 | For correct equation, aef in this form |
| Answer | Marks | Guidance |
|---|---|---|
| \(x = 2 + \lambda + \mu\), \(y = 2\lambda - 5\mu\), \(z = 1 - 2\mu\) | M1, M1 | For writing as 3 linear equations. For attempting to eliminate \(\lambda\) and \(\mu\) |
| \(\Rightarrow x - y + 3z = 3\) | A1 | For correct cartesian equation |
| \(\Rightarrow r \cdot [1, -1, 3] = 3\) | A1 | For correct equation, aef in this form |
| Answer | Marks |
|---|---|
| For \(r = a + tb\) |
| Answer | Marks | Guidance |
|---|---|---|
| \(b = [1, -1, 3] \times [7, 17, -3]\) | M1 | For attempting to find \(n_1 \times n_2\) |
| \(= k[2, -1, -1]\) | A1∇ | For a correct vector. If from \(n_1\) in (i). SR a correct vector may be stated without working. SR for \(a = [2, 2, 1]\) stated award M0 |
| e.g. \(x, y\) or \(z = 0\) in \(\begin{cases} x - y + 3z = 3 \\ 7x + 17y - 3z = 21 \end{cases}\) | M1 | For attempting to find a point on the line |
| \(\Rightarrow a = \left[0, \frac{3}{2}, \frac{3}{2}\right]\) OR \([3, 0, 0]\) OR \([1, 1, 1]\) | A1∇ | For a correct vector. If from equation in (i). SR a correct vector may be stated without working. SR for \(a = [2, 2, 1]\) stated award M0 |
| Line is (e.g.) \(r = [1, 1, 1] + t[2, -1, -1]\) | A1∇, 5 | For stating equation of line. If from \(a\) and \(b\). SR \(a = [2, 2, 1]\) stated award M0 |
| Answer | Marks | Guidance |
|---|---|---|
| Solve \(\begin{cases} x - y + 3z = 3 \\ 7x + 17y - 3z = 21 \end{cases}\) by eliminating one variable (e.g. \(z\)). Use parameter for another variable (e.g. \(x\)) to find other variables in terms of \(t\) | M1, M1 | For attempting to solve equations. For attempting to find parametric solution |
| (eg) \(y = \frac{3}{2} - \frac{1}{2}t\), \(z = \frac{3}{2} - \frac{1}{2}t\) | A1∇, A1∇ | For correct expression for one variable. For correct expression for the other variable. If from equation in (i) for both |
| Line is (eg) \(r = \left[0, \frac{3}{2}, \frac{3}{2}\right] + t[2, -1, -1]\) | A1∇ | For stating equation of line. If from parametric solutions |
| Answer | Marks | Guidance |
|---|---|---|
| eg \(x, y\) or \(z = 0\) in \(\begin{cases} x - y + 3z = 3 \\ 7x + 17y - 3z = 21 \end{cases}\) | M1 | For attempting to find a point on the line |
| \(\Rightarrow a = \left[0, \frac{3}{2}, \frac{3}{2}\right]\) OR \([3, 0, 0]\) OR \([1, 1, 1]\) | A1∇ | For a correct vector. If from equation in (i). SR a correct vector may be stated without working. SR for \(a = [2, 2, 1]\) stated award M0 |
| eg \([3, 0, 0] - [1, 1, 1]\) | M1 | For finding another point on the line and using it with the one already found to find \(b\) |
| \(b = k[2, -1, -1]\) | A1∇ | For a correct vector. If from equation in (i) |
| Line is (eg) \(r = [1, 1, 1] + t[2, -1, -1]\) | A1∇ | For stating equation of line. If from \(a\) and \(b\) |
| Answer | Marks | Guidance |
|---|---|---|
| A point on \(\Pi_1\) is \([2 + \lambda + \mu, 2\lambda - 5\mu, 1 - 2\mu]\) | M1 | For using parametric form for \(\Pi_1\) and substituting into \(\Pi_2\) |
| On \(\Pi_2 \Rightarrow [2 + \lambda + \mu, 2\lambda - 5\mu, 1 - 2\mu] \cdot [7, 17, -3] = 21\) | A1 | For correct unsimplified equation |
| \(\Rightarrow \lambda - 3\mu = -1\) | A1 | For correct equation |
| Line is (e.g.) \(r = [2, 2, 1] + (3\mu - 1)[1, 1, 0] + \mu[1, -5, -2]\) | M1 | For substituting into \(\Pi_1\) for \(\lambda\) or \(\mu\) |
| \(\Rightarrow r = [1, 1, 1]\) or \(\left[\frac{3}{2}, \frac{3}{2}, \frac{3}{2}\right] + t[2, -1, -1]\) | A1 | For stating equation of line |
**Part (i)**
| $n_1 = [1, 1, 0] \times [1, -5, -2]$ | M1 | For attempting to find vector product of the pair of direction vectors |
|---|---|---|
| $= [-2, 2, -6] = k[1, -1, 3]$ | A1 | For correct $n_1$ |
| Use $(2, 2, 1)$ | M1 | For substituting a point into equation |
| $\Rightarrow r \cdot [-2, 2, -6] = -6 \Rightarrow r \cdot [1, -1, 3] = 3$ | A1, 4 | For correct equation, aef in this form |
**METHOD 2**
| $x = 2 + \lambda + \mu$, $y = 2\lambda - 5\mu$, $z = 1 - 2\mu$ | M1, M1 | For writing as 3 linear equations. For attempting to eliminate $\lambda$ and $\mu$ |
|---|---|---|
| $\Rightarrow x - y + 3z = 3$ | A1 | For correct cartesian equation |
| $\Rightarrow r \cdot [1, -1, 3] = 3$ | A1 | For correct equation, aef in this form |
**Part (ii)**
| For $r = a + tb$ | | |
|---|---|---|
**METHOD 1**
| $b = [1, -1, 3] \times [7, 17, -3]$ | M1 | For attempting to find $n_1 \times n_2$ |
|---|---|---|
| $= k[2, -1, -1]$ | A1∇ | For a correct vector. If from $n_1$ in (i). SR a correct vector may be stated without working. SR for $a = [2, 2, 1]$ stated award M0 |
| e.g. $x, y$ or $z = 0$ in $\begin{cases} x - y + 3z = 3 \\ 7x + 17y - 3z = 21 \end{cases}$ | M1 | For attempting to find a point on the line |
| $\Rightarrow a = \left[0, \frac{3}{2}, \frac{3}{2}\right]$ OR $[3, 0, 0]$ OR $[1, 1, 1]$ | A1∇ | For a correct vector. If from equation in (i). SR a correct vector may be stated without working. SR for $a = [2, 2, 1]$ stated award M0 |
| Line is (e.g.) $r = [1, 1, 1] + t[2, -1, -1]$ | A1∇, 5 | For stating equation of line. If from $a$ and $b$. SR $a = [2, 2, 1]$ stated award M0 |
**METHOD 2**
| Solve $\begin{cases} x - y + 3z = 3 \\ 7x + 17y - 3z = 21 \end{cases}$ by eliminating one variable (e.g. $z$). Use parameter for another variable (e.g. $x$) to find other variables in terms of $t$ | M1, M1 | For attempting to solve equations. For attempting to find parametric solution |
|---|---|---|
| (eg) $y = \frac{3}{2} - \frac{1}{2}t$, $z = \frac{3}{2} - \frac{1}{2}t$ | A1∇, A1∇ | For correct expression for one variable. For correct expression for the other variable. If from equation in (i) for both |
| Line is (eg) $r = \left[0, \frac{3}{2}, \frac{3}{2}\right] + t[2, -1, -1]$ | A1∇ | For stating equation of line. If from parametric solutions |
**METHOD 3**
| eg $x, y$ or $z = 0$ in $\begin{cases} x - y + 3z = 3 \\ 7x + 17y - 3z = 21 \end{cases}$ | M1 | For attempting to find a point on the line |
|---|---|---|
| $\Rightarrow a = \left[0, \frac{3}{2}, \frac{3}{2}\right]$ OR $[3, 0, 0]$ OR $[1, 1, 1]$ | A1∇ | For a correct vector. If from equation in (i). SR a correct vector may be stated without working. SR for $a = [2, 2, 1]$ stated award M0 |
| eg $[3, 0, 0] - [1, 1, 1]$ | M1 | For finding another point on the line and using it with the one already found to find $b$ |
| $b = k[2, -1, -1]$ | A1∇ | For a correct vector. If from equation in (i) |
| Line is (eg) $r = [1, 1, 1] + t[2, -1, -1]$ | A1∇ | For stating equation of line. If from $a$ and $b$ |
**METHOD 4**
| A point on $\Pi_1$ is $[2 + \lambda + \mu, 2\lambda - 5\mu, 1 - 2\mu]$ | M1 | For using parametric form for $\Pi_1$ and substituting into $\Pi_2$ |
|---|---|---|
| On $\Pi_2 \Rightarrow [2 + \lambda + \mu, 2\lambda - 5\mu, 1 - 2\mu] \cdot [7, 17, -3] = 21$ | A1 | For correct unsimplified equation |
| $\Rightarrow \lambda - 3\mu = -1$ | A1 | For correct equation |
| Line is (e.g.) $r = [2, 2, 1] + (3\mu - 1)[1, 1, 0] + \mu[1, -5, -2]$ | M1 | For substituting into $\Pi_1$ for $\lambda$ or $\mu$ |
| $\Rightarrow r = [1, 1, 1]$ or $\left[\frac{3}{2}, \frac{3}{2}, \frac{3}{2}\right] + t[2, -1, -1]$ | A1 | For stating equation of line |
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6 The plane $\Pi _ { 1 }$ has equation $\mathbf { r } = \left( \begin{array} { l } 2 \\ 2 \\ 1 \end{array} \right) + \lambda \left( \begin{array} { l } 1 \\ 1 \\ 0 \end{array} \right) + \mu \left( \begin{array} { r } 1 \\ - 5 \\ - 2 \end{array} \right)$.\\
(i) Express the equation of $\Pi _ { 1 }$ in the form r.n $= p$.
The plane $\Pi _ { 2 }$ has equation $\mathbf { r } . \left( \begin{array} { r } 7 \\ 17 \\ - 3 \end{array} \right) = 21$.\\
(ii) Find an equation of the line of intersection of $\Pi _ { 1 }$ and $\Pi _ { 2 }$, giving your answer in the form $\mathbf { r } = \mathbf { a } + t \mathbf { b }$.
\hfill \mbox{\textit{OCR FP3 2009 Q6 [9]}}