OCR C1 2012 June — Question 9 11 marks

Exam BoardOCR
ModuleC1 (Core Mathematics 1)
Year2012
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypePerimeter or area constraint inequality
DifficultyModerate -0.3 This is a straightforward C1 inequality question requiring students to form and solve a quadratic inequality in part (i) and a compound linear inequality in part (ii). While it involves multiple steps and some algebraic manipulation, the techniques are standard and the problem-solving required is minimal—students simply translate the given constraints into algebraic form and solve using routine methods.
Spec1.02g Inequalities: linear and quadratic in single variable1.02h Express solutions: using 'and', 'or', set and interval notation

9
  1. A rectangular tile has length \(4 x \mathrm {~cm}\) and width \(( x + 3 ) \mathrm { cm }\). The area of the rectangle is less than \(112 \mathrm {~cm} ^ { 2 }\). By writing down and solving an inequality, determine the set of possible values of \(x\).
  2. A second rectangular tile of length \(4 y \mathrm {~cm}\) and width \(( y + 3 ) \mathrm { cm }\) has a rectangle of length \(2 y \mathrm {~cm}\) and width \(y \mathrm {~cm}\) removed from one corner as shown in the diagram. \includegraphics[max width=\textwidth, alt={}, center]{ae6cdd3c-0df9-4fec-b4bd-2237b585c766-3_358_757_479_662} Given that the perimeter of this tile is between 20 cm and 54 cm , determine the set of possible values of \(y\).

Question 9(i):
AnswerMarks Guidance
AnswerMarks Guidance
Area of tile \(= 4x(x+3)\)B1 Correct expression for area of rectangle (may be unsimplified)
\(4x(x+3) < 112\)B1\(\checkmark\) Correct inequality for their expression
\(4x^2 + 12x - 112 < 0\) Correct alternative forms for factorised inequality include: \((x+7)(4x-16) < 0\); \((4x+28)(x-4) < 0\); \((2x+14)(2x-8) < 0\) etc.
\(4(x+7)(x-4) < 0\)M1 Correct method to solve a three term quadratic
M1Chooses correct region for the quadratic inequality i.e. lower root \(< x <\) higher root. (May be implied by correct final answer)
\(-7 < x < 4\)A1
\(\therefore 0 < x < 4\)A1 [6] Restricts range to positive values of \(x\) CWO. Do not allow \(\leq\) for final A mark
Question 9(ii):
AnswerMarks Guidance
AnswerMarks Guidance
Perimeter \(= 4y + (y+3) + 2y + y + 2y + 3\)M1 Clear attempt to add lengths of all 6 edges. Allow \(<\) or \(\leq\) throughout part (ii)
A1Correct perimeter simplified to \(10y + 6\) seen
\(20 < 10y + 6 < 54\)B1 FT Correct inequalities for their expression. Can still be unsimplified here
M1Solving 2 linear equations or inequalities dealing with all 3 terms
\(1.4 < y < 4.8\)A1 [5] Accept "\(1.4 < y\), \(y < 4.8\)", "\(1.4 < y\) and \(y < 4.8\)" but NOT "\(1.4 < y\) or \(y < 4.8\)". Do not ISW if contradictory incorrect form follows correct answer
## Question 9(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Area of tile $= 4x(x+3)$ | B1 | Correct expression for area of rectangle (may be unsimplified) |
| $4x(x+3) < 112$ | B1$\checkmark$ | Correct inequality for their expression |
| $4x^2 + 12x - 112 < 0$ | | Correct alternative forms for factorised inequality include: $(x+7)(4x-16) < 0$; $(4x+28)(x-4) < 0$; $(2x+14)(2x-8) < 0$ etc. |
| $4(x+7)(x-4) < 0$ | M1 | Correct method to solve a three term quadratic |
| | M1 | Chooses correct region for the quadratic inequality i.e. lower root $< x <$ higher root. (May be implied by correct final answer) |
| $-7 < x < 4$ | A1 | |
| $\therefore 0 < x < 4$ | A1 [6] | Restricts range to positive values of $x$ **CWO**. **Do not allow $\leq$ for final A mark** |

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## Question 9(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Perimeter $= 4y + (y+3) + 2y + y + 2y + 3$ | M1 | **Clear** attempt to add lengths of all **6** edges. **Allow $<$ or $\leq$ throughout part (ii)** |
| | A1 | Correct perimeter simplified to $10y + 6$ seen |
| $20 < 10y + 6 < 54$ | B1 FT | Correct inequalities for their expression. Can still be unsimplified here |
| | M1 | Solving 2 linear equations or inequalities dealing with all 3 terms |
| $1.4 < y < 4.8$ | A1 [5] | Accept "$1.4 < y$, $y < 4.8$", "$1.4 < y$ **and** $y < 4.8$" but **NOT** "$1.4 < y$ **or** $y < 4.8$". **Do not ISW** if contradictory incorrect form follows correct answer |

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9 (i) A rectangular tile has length $4 x \mathrm {~cm}$ and width $( x + 3 ) \mathrm { cm }$. The area of the rectangle is less than $112 \mathrm {~cm} ^ { 2 }$. By writing down and solving an inequality, determine the set of possible values of $x$.\\
(ii) A second rectangular tile of length $4 y \mathrm {~cm}$ and width $( y + 3 ) \mathrm { cm }$ has a rectangle of length $2 y \mathrm {~cm}$ and width $y \mathrm {~cm}$ removed from one corner as shown in the diagram.\\
\includegraphics[max width=\textwidth, alt={}, center]{ae6cdd3c-0df9-4fec-b4bd-2237b585c766-3_358_757_479_662}

Given that the perimeter of this tile is between 20 cm and 54 cm , determine the set of possible values of $y$.

\hfill \mbox{\textit{OCR C1 2012 Q9 [11]}}