Edexcel M2 2005 June — Question 5 14 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2005
SessionJune
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions 1
TypeThree-particle sequential collisions
DifficultyStandard +0.3 This is a standard M2 momentum-collision problem requiring conservation of momentum and Newton's restitution law applied twice. Part (a) is routine calculation, part (b) requires comparing velocities after the second collision to verify no further collisions occur—straightforward but involves multiple steps and careful bookkeeping of directions.
Spec6.03b Conservation of momentum: 1D two particles6.03i Coefficient of restitution: e6.03j Perfectly elastic/inelastic: collisions6.03k Newton's experimental law: direct impact

5. Two small spheres \(A\) and \(B\) have mass \(3 m\) and \(2 m\) respectively. They are moving towards each other in opposite directions on a smooth horizontal plane, both with speed \(2 u\), when they collide directly. As a result of the collision, the direction of motion of \(B\) is reversed and its speed is unchanged.
  1. Find the coefficient of restitution between the spheres. Subsequently, \(B\) collides directly with another small sphere \(C\) of mass \(5 m\) which is at rest. The coefficient of restitution between \(B\) and \(C\) is \(\frac { 3 } { 5 }\).
  2. Show that, after \(B\) collides with \(C\), there will be no further collisions between the spheres.

Question 5:
Part (a):
AnswerMarks Guidance
WorkingMarks Notes
CLM: \(6mu - 4mu = 3mv + 4mu\)M1 A1
\(\Rightarrow v = -\frac{2}{3}u\)A1
NLI: \(2u - v = e \cdot 4u\)M1 A1
\(\Rightarrow 4eu = \frac{8}{3}u \Rightarrow e = \frac{2}{3}\)M1 A1
(7)
Part (b):
AnswerMarks Guidance
WorkingMarks Notes
\(5my + 2mx = 4mu\)M1 A1
\(y - x = \frac{3}{5} \cdot 2u = \frac{6}{5}u\)A1
Solve: \(x = -\frac{2}{7}u\)M1 A1
\(\frac{2}{7}u < \frac{2}{3}u\) so \(B\) does not overtake \(A\)M1
So no more collisionsA1 cso
(7)
## Question 5:

### Part (a):
| Working | Marks | Notes |
|---------|-------|-------|
| CLM: $6mu - 4mu = 3mv + 4mu$ | M1 A1 | |
| $\Rightarrow v = -\frac{2}{3}u$ | A1 | |
| NLI: $2u - v = e \cdot 4u$ | M1 A1 | |
| $\Rightarrow 4eu = \frac{8}{3}u \Rightarrow e = \frac{2}{3}$ | M1 A1 | |
| | **(7)** | |

### Part (b):
| Working | Marks | Notes |
|---------|-------|-------|
| $5my + 2mx = 4mu$ | M1 A1 | |
| $y - x = \frac{3}{5} \cdot 2u = \frac{6}{5}u$ | A1 | |
| Solve: $x = -\frac{2}{7}u$ | M1 A1 | |
| $\frac{2}{7}u < \frac{2}{3}u$ so $B$ does not overtake $A$ | M1 | |
| So no more collisions | A1 cso | |
| | **(7)** | |

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5. Two small spheres $A$ and $B$ have mass $3 m$ and $2 m$ respectively. They are moving towards each other in opposite directions on a smooth horizontal plane, both with speed $2 u$, when they collide directly. As a result of the collision, the direction of motion of $B$ is reversed and its speed is unchanged.
\begin{enumerate}[label=(\alph*)]
\item Find the coefficient of restitution between the spheres.

Subsequently, $B$ collides directly with another small sphere $C$ of mass $5 m$ which is at rest. The coefficient of restitution between $B$ and $C$ is $\frac { 3 } { 5 }$.
\item Show that, after $B$ collides with $C$, there will be no further collisions between the spheres.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2 2005 Q5 [14]}}