CAIE P3 2010 June — Question 8 9 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2010
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration with Partial Fractions
TypeSquare of partial fractions expression
DifficultyStandard +0.8 This question requires standard partial fractions (routine), then squaring the result and simplifying algebraically (moderately challenging manipulation), followed by integration of standard forms. The algebraic manipulation in part (ii) is non-trivial and requires careful expansion and collection of terms, elevating this above a typical textbook exercise. However, all techniques are standard for Further Pure Mathematics students.
Spec1.02y Partial fractions: decompose rational functions1.08j Integration using partial fractions

8
  1. Express \(\frac { 2 } { ( x + 1 ) ( x + 3 ) }\) in partial fractions.
  2. Using your answer to part (i), show that $$\left( \frac { 2 } { ( x + 1 ) ( x + 3 ) } \right) ^ { 2 } \equiv \frac { 1 } { ( x + 1 ) ^ { 2 } } - \frac { 1 } { x + 1 } + \frac { 1 } { x + 3 } + \frac { 1 } { ( x + 3 ) ^ { 2 } }$$
  3. Hence show that \(\int _ { 0 } ^ { 1 } \frac { 4 } { ( x + 1 ) ^ { 2 } ( x + 3 ) ^ { 2 } } \mathrm {~d} x = \frac { 7 } { 12 } - \ln \frac { 3 } { 2 }\).

Question 8:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
State or imply the form \(\frac{A}{x+1} + \frac{B}{x+3}\) and use a relevant method to find \(A\) or \(B\)M1
Obtain \(A = 1\), \(B = -1\)A1 [2]
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Square the result of part (i) and substitute the fractions of part (i)M1
Obtain the given answer correctlyA1 [2]
Part (iii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Integrate and obtain \(-\frac{1}{x+1} - \ln(x+1) + \ln(x+3) - \frac{1}{x+3}\)B3
Substitute limits correctly in an integral containing at least two terms of the correct formM1
Obtain given answer following full and exact workingA1 [5]
## Question 8:

### Part (i):

| Answer/Working | Mark | Guidance |
|---|---|---|
| State or imply the form $\frac{A}{x+1} + \frac{B}{x+3}$ and use a relevant method to find $A$ or $B$ | M1 | |
| Obtain $A = 1$, $B = -1$ | A1 | [2] |

### Part (ii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Square the result of part (i) and substitute the fractions of part (i) | M1 | |
| Obtain the given answer correctly | A1 | [2] |

### Part (iii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Integrate and obtain $-\frac{1}{x+1} - \ln(x+1) + \ln(x+3) - \frac{1}{x+3}$ | B3 | |
| Substitute limits correctly in an integral containing at least two terms of the correct form | M1 | |
| Obtain given answer following full and exact working | A1 | [5] |

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8 (i) Express $\frac { 2 } { ( x + 1 ) ( x + 3 ) }$ in partial fractions.\\
(ii) Using your answer to part (i), show that

$$\left( \frac { 2 } { ( x + 1 ) ( x + 3 ) } \right) ^ { 2 } \equiv \frac { 1 } { ( x + 1 ) ^ { 2 } } - \frac { 1 } { x + 1 } + \frac { 1 } { x + 3 } + \frac { 1 } { ( x + 3 ) ^ { 2 } }$$

(iii) Hence show that $\int _ { 0 } ^ { 1 } \frac { 4 } { ( x + 1 ) ^ { 2 } ( x + 3 ) ^ { 2 } } \mathrm {~d} x = \frac { 7 } { 12 } - \ln \frac { 3 } { 2 }$.

\hfill \mbox{\textit{CAIE P3 2010 Q8 [9]}}