OCR MEI FP1 2007 January — Question 6 8 marks

Exam BoardOCR MEI
ModuleFP1 (Further Pure Mathematics 1)
Year2007
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProof by induction
TypeProve summation formula
DifficultyModerate -0.5 This is a standard textbook induction proof of a well-known summation formula. While it requires understanding of the induction framework and algebraic manipulation to verify the inductive step, it follows a completely routine template with no novel insight required. The algebra is straightforward compared to more complex induction proofs, making it slightly easier than average but still requiring proper technique.
Spec4.01a Mathematical induction: construct proofs

6 Prove by induction that \(\sum _ { r = 1 } ^ { n } r ^ { 2 } = \frac { 1 } { 6 } n ( n + 1 ) ( 2 n + 1 )\).

Prove by induction that \(\sum_{r=1}^{n} r^2 = \frac{1}{6}n(n+1)(2n+1)\). [8]
Prove by induction that $\sum_{r=1}^{n} r^2 = \frac{1}{6}n(n+1)(2n+1)$. [8]
6 Prove by induction that $\sum _ { r = 1 } ^ { n } r ^ { 2 } = \frac { 1 } { 6 } n ( n + 1 ) ( 2 n + 1 )$.

\hfill \mbox{\textit{OCR MEI FP1 2007 Q6 [8]}}