OCR MEI C4 2008 January — Question 4 7 marks

Exam BoardOCR MEI
ModuleC4 (Core Mathematics 4)
Year2008
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeShow equation reduces to tan form
DifficultyModerate -0.8 This is a straightforward application of the addition formula for sine, followed by basic algebraic manipulation to isolate tan θ. Part (i) requires expanding sin(θ+45°) using the given exact values and rearranging to get tan θ = (√2-1), which is routine. Part (ii) involves using a calculator to find angles from the tan value. The question tests standard technique with no problem-solving insight required, making it easier than average.
Spec1.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

4 The angle \(\theta\) satisfies the equation \(\sin \left( \theta + 45 ^ { \circ } \right) = \cos \theta\).
  1. Using the exact values of \(\sin 45 ^ { \circ }\) and \(\cos 45 ^ { \circ }\), show that \(\tan \theta = \sqrt { 2 } - 1\).
  2. Find the values of \(\theta\) for \(0 ^ { \circ } < \theta < 360 ^ { \circ }\).

\(1 - EH = 1 - CG = 1 - (\phi - 1)\)
AnswerMarks
\(= 2 - \phi = 2 - \left(\frac{1 + \sqrt{5}}{2}\right)\)M1 A1
\(= \frac{3 - \sqrt{5}}{2}\)A1
$1 - EH = 1 - CG = 1 - (\phi - 1)$

$= 2 - \phi = 2 - \left(\frac{1 + \sqrt{5}}{2}\right)$ | M1 A1 |

$= \frac{3 - \sqrt{5}}{2}$ | A1 |
4 The angle $\theta$ satisfies the equation $\sin \left( \theta + 45 ^ { \circ } \right) = \cos \theta$.\\
(i) Using the exact values of $\sin 45 ^ { \circ }$ and $\cos 45 ^ { \circ }$, show that $\tan \theta = \sqrt { 2 } - 1$.\\
(ii) Find the values of $\theta$ for $0 ^ { \circ } < \theta < 360 ^ { \circ }$.

\hfill \mbox{\textit{OCR MEI C4 2008 Q4 [7]}}