Edexcel M3 2013 June — Question 7 16 marks

Exam BoardEdexcel
ModuleM3 (Mechanics 3)
Year2013
SessionJune
Marks16
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 2
TypeVertical circle: string becomes slack
DifficultyChallenging +1.2 This is a standard M3 vertical circle problem with projectile motion follow-up. Part (a) requires routine energy conservation and circular motion equation application. Part (b) uses the slack condition (T=0). Part (c) involves standard projectile motion equations. While multi-step, all techniques are textbook exercises with no novel insight required—slightly above average due to length and algebraic manipulation.
Spec3.02f Non-uniform acceleration: using differentiation and integration3.02g Two-dimensional variable acceleration6.02i Conservation of energy: mechanical energy principle6.02j Conservation with elastics: springs and strings

7. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{f6ab162c-8473-4464-ad62-87a359d85ab3-12_499_833_262_664} \captionsetup{labelformat=empty} \caption{Figure 6}
\end{figure} A particle \(P\) of mass \(5 m\) is attached to one end of a light inextensible string of length \(a\). The other end of the string is attached to a fixed point \(O\). The particle is held at the point \(A\), where \(O A = a\) and \(O A\) is horizontal, as shown in Figure 6. The particle is projected vertically downwards with speed \(\sqrt { } \left( \frac { 9 a g } { 5 } \right)\). When the string makes an angle \(\theta\) with the downward vertical through \(O\) and the string is still taut, the tension in the string is \(T\).
  1. Show that \(T = 3 m g ( 5 \cos \theta + 3 )\). At the instant when the particle reaches the point \(B\) the string becomes slack.
  2. Find the speed of \(P\) at \(B\). At time \(t = 0 , P\) is at \(B\). At time \(t\), before the string becomes taut once more, the coordinates of \(P\) are \(( x , y )\) referred to horizontal and vertical axes with origin \(O\). The \(x\)-axis is directed along \(O A\) produced and the \(y\)-axis is vertically upward.
  3. Find
    1. \(x\) in terms of \(t , a\) and \(g\),
    2. \(y\) in terms of \(t , a\) and \(g\).

7.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{f6ab162c-8473-4464-ad62-87a359d85ab3-12_499_833_262_664}
\captionsetup{labelformat=empty}
\caption{Figure 6}
\end{center}
\end{figure}

A particle $P$ of mass $5 m$ is attached to one end of a light inextensible string of length $a$. The other end of the string is attached to a fixed point $O$. The particle is held at the point $A$, where $O A = a$ and $O A$ is horizontal, as shown in Figure 6. The particle is projected vertically downwards with speed $\sqrt { } \left( \frac { 9 a g } { 5 } \right)$. When the string makes an angle $\theta$ with the downward vertical through $O$ and the string is still taut, the tension in the string is $T$.
\begin{enumerate}[label=(\alph*)]
\item Show that $T = 3 m g ( 5 \cos \theta + 3 )$.

At the instant when the particle reaches the point $B$ the string becomes slack.
\item Find the speed of $P$ at $B$.

At time $t = 0 , P$ is at $B$.

At time $t$, before the string becomes taut once more, the coordinates of $P$ are $( x , y )$ referred to horizontal and vertical axes with origin $O$. The $x$-axis is directed along $O A$ produced and the $y$-axis is vertically upward.
\item Find
\begin{enumerate}[label=(\roman*)]
\item $x$ in terms of $t , a$ and $g$,
\item $y$ in terms of $t , a$ and $g$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{Edexcel M3 2013 Q7 [16]}}