Edexcel M3 2013 June — Question 1 6 marks

Exam BoardEdexcel
ModuleM3 (Mechanics 3)
Year2013
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 1
TypeRotating disc with friction
DifficultyModerate -0.3 This is a straightforward application of circular motion with friction. Students need to convert angular speed to rad/s, apply F=mrω², set friction equal to centripetal force, and solve for μ. It's a standard M3 question requiring routine application of formulas with minimal problem-solving insight, making it slightly easier than average.
Spec3.03r Friction: concept and vector form3.03t Coefficient of friction: F <= mu*R model6.05b Circular motion: v=r*omega and a=v^2/r6.05c Horizontal circles: conical pendulum, banked tracks

1. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{f6ab162c-8473-4464-ad62-87a359d85ab3-02_515_976_285_484} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} A rough disc is rotating in a horizontal plane with constant angular speed 20 revolutions per minute about a fixed vertical axis through its centre \(O\). A particle \(P\) rests on the disc at a distance 0.4 m from \(O\), as shown in Figure 1. The coefficient of friction between \(P\) and the disc is \(\mu\). The particle \(P\) is on the point of slipping. Find the value of \(\mu\).

1.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{f6ab162c-8473-4464-ad62-87a359d85ab3-02_515_976_285_484}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

A rough disc is rotating in a horizontal plane with constant angular speed 20 revolutions per minute about a fixed vertical axis through its centre $O$. A particle $P$ rests on the disc at a distance 0.4 m from $O$, as shown in Figure 1. The coefficient of friction between $P$ and the disc is $\mu$. The particle $P$ is on the point of slipping.

Find the value of $\mu$.\\

\hfill \mbox{\textit{Edexcel M3 2013 Q1 [6]}}