OCR C3 2007 June — Question 7 9 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2007
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeSketch reciprocal function graphs
DifficultyModerate -0.3 This is a straightforward C3 question testing standard knowledge of reciprocal trig functions. Part (i) is routine graph sketching from memory, part (ii) is direct calculator work (cos x = 1/3), and part (iii) requires the standard identity manipulation sec θ = 5 cosec θ → sin θ = 5 cos θ → tan θ = 5, then calculator work. All techniques are textbook exercises with no novel problem-solving required, making it slightly easier than average.
Spec1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.05o Trigonometric equations: solve in given intervals

7
  1. Sketch the graph of \(y = \sec x\) for \(0 \leqslant x \leqslant 2 \pi\).
  2. Solve the equation \(\sec x = 3\) for \(0 \leqslant x \leqslant 2 \pi\), giving the roots correct to 3 significant figures.
  3. Solve the equation \(\sec \theta = 5 \operatorname { cosec } \theta\) for \(0 \leqslant \theta \leqslant 2 \pi\), giving the roots correct to 3 significant figures.

AnswerMarks Guidance
(i) Show correct general shape (alternating above and below x-axis)M1 with no branch reaching x-axis
Draw (more or less correct) sketchA1 2 with at least one of 1 and –1 indicated or clearly implied
(ii) Attempt solution of \(\cos x = \frac{1}{4}\)M1 maybe implied; or equiv
Obtain \(1.23\) or \(0.392\pi\)A1 or greater accuracy
Obtain \(5.05\) or \(1.61\pi\)A1 3 or greater accuracy and no others within \(0 \le x \le 2\pi\); penalise answer(s) to 2sf only once
(iii) Either: Obtain equation of form \(\tan \theta = k\)M1 any constant \(k\); maybe implied
Obtain \(\tan \theta = 5\)A1
Obtain two values only of form \(\theta, \theta + \pi\)M1 within \(0 \le x \le 2\pi\); allow degrees at this stage
Obtain \(1.37\) and \(4.51\) (or \(0.437\pi\) and \(1.44\pi\))A1 4 allow ±1 in third sig fig; or greater accuracy
Or: (for methods which involve squaring etc.)
Attempt to obtain eqn in one trig ratioM1
Obtain correct valueA1 \(\tan^2 \theta = 25, \cos^2 \theta = \frac{1}{26}, \ldots\)
Attempt solution at least to find one value in first quadrant and one value in thirdM1
Obtain \(1.37\) and \(4.51\) (or equivs as above)A1 ignoring values in second and fourth quadrants
(i) Show correct general shape (alternating above and below x-axis) | M1 | with no branch reaching x-axis
Draw (more or less correct) sketch | A1 | 2 with at least one of 1 and –1 indicated or clearly implied

(ii) Attempt solution of $\cos x = \frac{1}{4}$ | M1 | maybe implied; or equiv
Obtain $1.23$ or $0.392\pi$ | A1 | or greater accuracy
Obtain $5.05$ or $1.61\pi$ | A1 | 3 or greater accuracy and no others within $0 \le x \le 2\pi$; penalise answer(s) to 2sf only once

(iii) Either: Obtain equation of form $\tan \theta = k$ | M1 | any constant $k$; maybe implied
Obtain $\tan \theta = 5$ | A1 |
Obtain two values only of form $\theta, \theta + \pi$ | M1 | within $0 \le x \le 2\pi$; allow degrees at this stage
Obtain $1.37$ and $4.51$ (or $0.437\pi$ and $1.44\pi$) | A1 | 4 allow ±1 in third sig fig; or greater accuracy

Or: (for methods which involve squaring etc.) | |
Attempt to obtain eqn in one trig ratio | M1 |
Obtain correct value | A1 | $\tan^2 \theta = 25, \cos^2 \theta = \frac{1}{26}, \ldots$
Attempt solution at least to find one value in first quadrant and one value in third | M1 |
Obtain $1.37$ and $4.51$ (or equivs as above) | A1 | ignoring values in second and fourth quadrants

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7 (i) Sketch the graph of $y = \sec x$ for $0 \leqslant x \leqslant 2 \pi$.\\
(ii) Solve the equation $\sec x = 3$ for $0 \leqslant x \leqslant 2 \pi$, giving the roots correct to 3 significant figures.\\
(iii) Solve the equation $\sec \theta = 5 \operatorname { cosec } \theta$ for $0 \leqslant \theta \leqslant 2 \pi$, giving the roots correct to 3 significant figures.

\hfill \mbox{\textit{OCR C3 2007 Q7 [9]}}