OCR C3 2007 June — Question 5 7 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2007
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Functions
TypeHalf-life and doubling time
DifficultyModerate -0.3 This is a straightforward exponential decay question requiring standard techniques: (i) solving 120 = 240e^(-0.04t) using logarithms, and (ii) differentiating to get dm/dt = -9.6e^(-0.04t), then solving -9.6e^(-0.04t) = -2.1. Both parts are routine applications of C3 material with no conceptual challenges, making it slightly easier than average.
Spec1.06i Exponential growth/decay: in modelling context1.07k Differentiate trig: sin(kx), cos(kx), tan(kx)

5 A substance is decaying in such a way that its mass, m kg , at a time t years from now is given by the formula $$\mathrm { m } = 240 \mathrm { e } ^ { - 0.04 \mathrm { t } }$$
  1. Find the time taken for the substance to halve its mass.
  2. Find the value of \(t\) for which the mass is decreasing at a rate of 2.1 kg per year.

AnswerMarks Guidance
(i) State \(e^{-0.04t} = 0.5\)B1 or equiv
Attempt solution of equation of form \(e^{-0.04t} = k\)M1 using sound process; maybe implied
Obtain \(17\)A1 3 or greater accuracy (17.328…)
(ii) Differentiate to obtain form \(ke^{-0.04t}\)*M1 constant \(k\) different from 240
Obtain \((\pm) 9.6e^{-0.04t}\)A1 or (unsimplified) equiv
Equate attempt at first derivative to \((\pm) 2.1\) and attempt solutionM1 dep *M; method may be implied
Obtain \(38\)A1 4 or greater accuracy (37.9956…)
(i) State $e^{-0.04t} = 0.5$ | B1 | or equiv
Attempt solution of equation of form $e^{-0.04t} = k$ | M1 | using sound process; maybe implied
Obtain $17$ | A1 | 3 or greater accuracy (17.328…)

(ii) Differentiate to obtain form $ke^{-0.04t}$ | *M1 | constant $k$ different from 240
Obtain $(\pm) 9.6e^{-0.04t}$ | A1 | or (unsimplified) equiv
Equate attempt at first derivative to $(\pm) 2.1$ and attempt solution | M1 | dep *M; method may be implied
Obtain $38$ | A1 | 4 or greater accuracy (37.9956…)

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5 A substance is decaying in such a way that its mass, m kg , at a time t years from now is given by the formula

$$\mathrm { m } = 240 \mathrm { e } ^ { - 0.04 \mathrm { t } }$$

(i) Find the time taken for the substance to halve its mass.\\
(ii) Find the value of $t$ for which the mass is decreasing at a rate of 2.1 kg per year.

\hfill \mbox{\textit{OCR C3 2007 Q5 [7]}}