| Exam Board | CAIE |
|---|---|
| Module | P2 (Pure Mathematics 2) |
| Year | 2006 |
| Session | June |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Factor & Remainder Theorem |
| Type | Two factors given |
| Difficulty | Moderate -0.8 This is a straightforward application of the Factor Theorem requiring substitution of x=1 and x=-2 to create two simultaneous equations, then solving for a and b. Part (ii) involves simple factorization or polynomial division. The question is routine with clear structure and standard techniques, making it easier than average but not trivial since it requires algebraic manipulation across multiple steps. |
| Spec | 1.02f Solve quadratic equations: including in a function of unknown1.02j Manipulate polynomials: expanding, factorising, division, factor theorem |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Substitute \(x = 1\) or \(x = -2\) and equate to zero | M1 | |
| Obtain a correct equation, e.g. \(a + b - 5 = 0\) | A1 | |
| Obtain a second correct equation, e.g. \(-8a + 4b + 4 = 0\) | A1 | |
| Solve a relevant pair of equations for \(a\) or for \(b\) | M1 | |
| Obtain \(a = 2\) and \(b = 3\) | A1 | Total: 5 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Substitute for \(a\) and \(b\) and either divide by \((x-1)(x+2)\) or attempt third factor by inspection | M1 | |
| Obtain answer \(2x + 1\) | A1 | Total: 2 |
## Question 4:
### Part (i):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Substitute $x = 1$ or $x = -2$ and equate to zero | M1 | |
| Obtain a correct equation, e.g. $a + b - 5 = 0$ | A1 | |
| Obtain a second correct equation, e.g. $-8a + 4b + 4 = 0$ | A1 | |
| Solve a relevant pair of equations for $a$ or for $b$ | M1 | |
| Obtain $a = 2$ and $b = 3$ | A1 | Total: 5 |
### Part (ii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Substitute for $a$ and $b$ and either divide by $(x-1)(x+2)$ or attempt third factor by inspection | M1 | |
| Obtain answer $2x + 1$ | A1 | Total: 2 |
---4 The cubic polynomial $a x ^ { 3 } + b x ^ { 2 } - 3 x - 2$, where $a$ and $b$ are constants, is denoted by $\mathrm { p } ( x )$. It is given that $( x - 1 )$ and $( x + 2 )$ are factors of $\mathrm { p } ( x )$.\\
(i) Find the values of $a$ and $b$.\\
(ii) When $a$ and $b$ have these values, find the other linear factor of $\mathrm { p } ( x )$.
\hfill \mbox{\textit{CAIE P2 2006 Q4 [7]}}