CAIE P2 2006 June — Question 6 9 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2006
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeShow convergence to specific root
DifficultyStandard +0.3 This is a standard fixed-point iteration question requiring sketching graphs to show uniqueness, verifying a root interval by substitution, algebraic manipulation to show convergence to the correct root, and performing iterations. All steps are routine A-level techniques with no novel insight required, making it slightly easier than average.
Spec1.02q Use intersection points: of graphs to solve equations1.06d Natural logarithm: ln(x) function and properties1.09a Sign change methods: locate roots1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

6
  1. By sketching a suitable pair of graphs, show that there is only one value of \(x\) that is a root of the equation \(x = 9 \mathrm { e } ^ { - 2 x }\).
  2. Verify, by calculation, that this root lies between 1 and 2 .
  3. Show that, if a sequence of values given by the iterative formula $$x _ { n + 1 } = \frac { 1 } { 2 } \left( \ln 9 - \ln x _ { n } \right)$$ converges, then it converges to the root of the equation given in part (i).
  4. Use the iterative formula, with \(x _ { 1 } = 1\), to calculate the root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

Question 6:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Make recognisable sketch of appropriate exponential curve, e.g. \(y = 9e^{-2x}\)B1
Sketch appropriate second curve, e.g. \(y = x\) correctly and justify the given statementB1 Total: 2
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Consider sign of \(x - 9e^{-2x}\) at \(x = 1\) and \(x = 2\), or equivalentM1
Complete the argument correctly with appropriate calculationsA1 Total: 2
Part (iii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
State or imply the equation \(x = \frac{1}{2}(\ln 9 - \ln x)\)B1
Rearrange this in the form given in part (i), or work vice versaB1 Total: 2
Part (iv):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Use the iterative formula correctly at least onceM1
Obtain final answer \(x = 1.07\)A1
Show sufficient iterations to justify accuracy to 2 d.p. or show sign change in interval \((1.065, 1.075)\)A1 Total: 3
## Question 6:

### Part (i):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Make recognisable sketch of appropriate exponential curve, e.g. $y = 9e^{-2x}$ | B1 | |
| Sketch appropriate second curve, e.g. $y = x$ correctly and justify the given statement | B1 | Total: 2 |

### Part (ii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Consider sign of $x - 9e^{-2x}$ at $x = 1$ and $x = 2$, or equivalent | M1 | |
| Complete the argument correctly with appropriate calculations | A1 | Total: 2 |

### Part (iii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| State or imply the equation $x = \frac{1}{2}(\ln 9 - \ln x)$ | B1 | |
| Rearrange this in the form given in part (i), or work vice versa | B1 | Total: 2 |

### Part (iv):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Use the iterative formula correctly at least once | M1 | |
| Obtain final answer $x = 1.07$ | A1 | |
| Show sufficient iterations to justify accuracy to 2 d.p. or show sign change in interval $(1.065, 1.075)$ | A1 | Total: 3 |

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6 (i) By sketching a suitable pair of graphs, show that there is only one value of $x$ that is a root of the equation $x = 9 \mathrm { e } ^ { - 2 x }$.\\
(ii) Verify, by calculation, that this root lies between 1 and 2 .\\
(iii) Show that, if a sequence of values given by the iterative formula

$$x _ { n + 1 } = \frac { 1 } { 2 } \left( \ln 9 - \ln x _ { n } \right)$$

converges, then it converges to the root of the equation given in part (i).\\
(iv) Use the iterative formula, with $x _ { 1 } = 1$, to calculate the root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

\hfill \mbox{\textit{CAIE P2 2006 Q6 [9]}}