OCR MEI C2 2007 January — Question 6 4 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Year2007
SessionJanuary
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrigonometric equations in context
TypeSketch basic trig graph and solve
DifficultyEasy -1.2 This is a straightforward C2 question requiring a standard sine curve sketch and solving a basic trig equation using calculator + symmetry. It involves routine procedures with no problem-solving insight needed, making it easier than average but not trivial since students must correctly identify both solutions in the given range.
Spec1.05f Trigonometric function graphs: symmetries and periodicities1.05o Trigonometric equations: solve in given intervals
6 Sketch the curve \(y = \sin x\) for \(0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }\).
Solve the equation \(\sin x = - 0.68\) for \(0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }\).
Question 6:
AnswerMarks Guidance
Correct sketch of \(\sin x\), \(0° \leq x \leq 360°\)B1 Correct shape and key values
\(x = \arcsin(-0.68) = -42.8°\)M1 Finding reference angle
\(x = 180° + 42.8° = 222.8°\)A1
\(x = 360° - 42.8° = 317.2°\)A1 Both answers required; accept \(222.8°\) and \(317.2°\) 
## Question 6:
Correct sketch of $\sin x$, $0° \leq x \leq 360°$ | B1 | Correct shape and key values
$x = \arcsin(-0.68) = -42.8°$ | M1 | Finding reference angle
$x = 180° + 42.8° = 222.8°$ | A1 | 
$x = 360° - 42.8° = 317.2°$ | A1 | Both answers required; accept $222.8°$ and $317.2°$

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6 Sketch the curve $y = \sin x$ for $0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }$.\\
Solve the equation $\sin x = - 0.68$ for $0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }$.

\hfill \mbox{\textit{OCR MEI C2 2007 Q6 [4]}}
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