OCR C2 2006 January — Question 7 8 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Year2006
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLaws of Logarithms
TypeTwo unrelated log/algebra parts - linked parts (hence)
DifficultyModerate -0.5 This question tests standard logarithm laws (quotient, product, power rules) in part (i), which is routine recall. Part (ii) requires algebraic manipulation to solve for y, but follows a predictable pattern once the laws are applied. The multi-step nature and algebraic solving elevates it slightly above pure recall, but it remains a standard textbook exercise with no novel insight required.
Spec1.06f Laws of logarithms: addition, subtraction, power rules

7
  1. Express each of the following in terms of \(\log _ { 10 } x\) and \(\log _ { 10 } y\).
    1. \(\log _ { 10 } \left( \frac { x } { y } \right)\)
    2. \(\log _ { 10 } \left( 10 x ^ { 2 } y \right)\)
    3. Given that $$2 \log _ { 10 } \left( \frac { x } { y } \right) = 1 + \log _ { 10 } \left( 10 x ^ { 2 } y \right)$$ find the value of \(y\) correct to 3 decimal places.

(i)(a)
AnswerMarks Guidance
\(\log_{10}x - \log_{10}y\)B1 For the correct answer
M1Sum of three log terms involving 10, \(x^2\), \(y\)
A1
A1For correct term \(2\log_{10}x\) For both correct terms 1 and \(\log_{10}y\)
(i)(b)
AnswerMarks
\(1 + 2\log_{10} + \log_{10}y\)M1
(ii)
AnswerMarks Guidance
\(2\log_{10}x - 2\log_{10}y = 2 + 2\log_{10}x + \log_{10}y\)M1 For relevant use of results from (i)
\(\text{Hence } 3\log_{10}y = -2\)A1 For a correct, unsimplified, equation in \(\log_{10}y\) only
\(y = 10^{-2/3} \approx 0.215\)M1 For correct use of \(a = \log_{10}c \Leftrightarrow c = 10^a\)
A1For the correct value 0.215
**(i)(a)**
$\log_{10}x - \log_{10}y$ | B1 | For the correct answer
| M1 | Sum of three log terms involving 10, $x^2$, $y$
| A1 | 
| A1 | For correct term $2\log_{10}x$ For both correct terms 1 and $\log_{10}y$

**(i)(b)**
$1 + 2\log_{10} + \log_{10}y$ | M1 |

**(ii)**
$2\log_{10}x - 2\log_{10}y = 2 + 2\log_{10}x + \log_{10}y$ | M1 | For relevant use of results from (i)
$\text{Hence } 3\log_{10}y = -2$ | A1 | For a correct, unsimplified, equation in $\log_{10}y$ only
$y = 10^{-2/3} \approx 0.215$ | M1 | For correct use of $a = \log_{10}c \Leftrightarrow c = 10^a$
| A1 | For the correct value 0.215

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7 (i) Express each of the following in terms of $\log _ { 10 } x$ and $\log _ { 10 } y$.
\begin{enumerate}[label=(\alph*)]
\item $\log _ { 10 } \left( \frac { x } { y } \right)$
\item $\log _ { 10 } \left( 10 x ^ { 2 } y \right)$\\
(ii) Given that

$$2 \log _ { 10 } \left( \frac { x } { y } \right) = 1 + \log _ { 10 } \left( 10 x ^ { 2 } y \right)$$

find the value of $y$ correct to 3 decimal places.
\end{enumerate}

\hfill \mbox{\textit{OCR C2 2006 Q7 [8]}}