OCR C2 2006 January — Question 6 8 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Year2006
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndefinite & Definite Integrals
TypeImproper integral evaluation
DifficultyStandard +0.3 Part (a) is routine integration using power rule. Part (b)(i) requires standard integration and substitution of limits. Part (b)(ii) introduces improper integrals but only requires taking a limit as a→∞ of the previous result—slightly above average due to the improper integral concept, but still straightforward application of technique.
Spec1.08b Integrate x^n: where n != -1 and sums1.08d Evaluate definite integrals: between limits

6
  1. Find \(\int \left( x ^ { \frac { 1 } { 2 } } + 4 \right) \mathrm { d } x\).
    1. Find the value, in terms of \(a\), of \(\int _ { 1 } ^ { a } 4 x ^ { - 2 } \mathrm {~d} x\), where \(a\) is a constant greater than 1 .
    2. Deduce the value of \(\int _ { 1 } ^ { \infty } 4 x ^ { - 2 } \mathrm {~d} x\).

(a)
AnswerMarks Guidance
\(\frac{2}{3}x^2 + 4x + c\)M1 For \(kx^2\)
A1For correct first term \(\frac{2}{3}x^2\), or equiv
B1For correct second term 4x
B1For \(+c\)
(b)(i)
AnswerMarks Guidance
\(\int 4x^{-1}\text{d}x = [-4x^{-1}]_1^a\)M1 Obtain integral of the form \(kx^{-1}\)
M1Use limits \(x = a\) and \(x = 1\)
A1Obtain \(4 - \frac{4}{a}\), or equivalent
(b)(ii)
AnswerMarks Guidance
\(4\)B1√ State 4, or legitimate conclusion from their (b)(i)
**(a)**
$\frac{2}{3}x^2 + 4x + c$ | M1 | For $kx^2$
| A1 | For correct first term $\frac{2}{3}x^2$, or equiv
| B1 | For correct second term 4x
| B1 | For $+c$

**(b)(i)**
$\int 4x^{-1}\text{d}x = [-4x^{-1}]_1^a$ | M1 | Obtain integral of the form $kx^{-1}$
| M1 | Use limits $x = a$ and $x = 1$
| A1 | Obtain $4 - \frac{4}{a}$, or equivalent

**(b)(ii)**
$4$ | B1√ | State 4, or legitimate conclusion from their (b)(i)

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6
\begin{enumerate}[label=(\alph*)]
\item Find $\int \left( x ^ { \frac { 1 } { 2 } } + 4 \right) \mathrm { d } x$.
\item \begin{enumerate}[label=(\roman*)]
\item Find the value, in terms of $a$, of $\int _ { 1 } ^ { a } 4 x ^ { - 2 } \mathrm {~d} x$, where $a$ is a constant greater than 1 .
\item Deduce the value of $\int _ { 1 } ^ { \infty } 4 x ^ { - 2 } \mathrm {~d} x$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{OCR C2 2006 Q6 [8]}}