Standard +0.8 This is a two-sample proportion test requiring calculation of pooled proportion, test statistic, and finding the exact significance level (p-value) rather than comparing to standard critical values. While the method is standard for S3, the 'smallest significance level' phrasing requires understanding of p-values and careful calculation, making it moderately harder than routine hypothesis testing questions.
4 A study in 1981 investigated the effect of water fluoridation on children's dental health. In a town with fluoridation, 61 out of a random sample of 107 children showed signs of increased tooth decay after six months. In a town without fluoridation the corresponding number was 106 out of a random sample of 143 children. The population proportions of children with increased tooth decay are denoted by \(p _ { 1 }\) and \(p _ { 2 }\) for the towns with fluoridation and without fluoridation respectively. A test is carried out of the null hypothesis \(p _ { 1 } = p _ { 2 }\) against the alternative hypothesis \(p _ { 1 } < p _ { 2 }\). Find the smallest significance level at which the null hypothesis is rejected.
4 A study in 1981 investigated the effect of water fluoridation on children's dental health. In a town with fluoridation, 61 out of a random sample of 107 children showed signs of increased tooth decay after six months. In a town without fluoridation the corresponding number was 106 out of a random sample of 143 children. The population proportions of children with increased tooth decay are denoted by $p _ { 1 }$ and $p _ { 2 }$ for the towns with fluoridation and without fluoridation respectively. A test is carried out of the null hypothesis $p _ { 1 } = p _ { 2 }$ against the alternative hypothesis $p _ { 1 } < p _ { 2 }$. Find the smallest significance level at which the null hypothesis is rejected.
\hfill \mbox{\textit{OCR S3 2011 Q4 [7]}}