| Exam Board | OCR MEI |
|---|---|
| Module | C1 (Core Mathematics 1) |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Curve Sketching |
| Type | Single transformation between given equations |
| Difficulty | Easy -1.2 This is a straightforward C1 question testing basic transformations and curve sketching. Part (i) requires simple recall that y=(x+4)² is a horizontal translation of y=x² by 4 units left. Part (ii) is routine sketching of a parabola with a vertical shift, requiring only plotting the vertex and intercepts. Both parts are standard textbook exercises with no problem-solving or novel insight required. |
| Spec | 1.02n Sketch curves: simple equations including polynomials1.02w Graph transformations: simple transformations of f(x) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Translation | B1 | 0 for shift/move |
| By \(\begin{pmatrix}-4\\0\end{pmatrix}\) or 4 [units] to left | B1 | Or 4 units in negative \(x\) direction oe |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Sketch of parabola right way up and with minimum on negative \(y\)-axis | B1 | Mark intent for both marks |
| Minimum at \((0, -4)\) and graph through \(-2\) and \(2\) on \(x\)-axis | B1 | Must be labelled or shown nearby |
## Question 6(i):
| Answer | Mark | Guidance |
|--------|------|----------|
| Translation | B1 | **0** for shift/move |
| By $\begin{pmatrix}-4\\0\end{pmatrix}$ or 4 [units] to left | B1 | Or 4 units in negative $x$ direction oe |
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## Question 6(ii):
| Answer | Mark | Guidance |
|--------|------|----------|
| Sketch of parabola right way up and with minimum on negative $y$-axis | B1 | Mark intent for both marks |
| Minimum at $(0, -4)$ and graph through $-2$ and $2$ on $x$-axis | B1 | Must be labelled or shown nearby |
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6\\
(i) Describe fully the transformation which maps the curve $y = x ^ { 2 }$ onto the curve $y = ( x + 4 ) ^ { 2 }$.\\
(ii) Sketch the graph of $y = x ^ { 2 } - 4$.
\hfill \mbox{\textit{OCR MEI C1 Q6 [4]}}