OCR MEI C1 — Question 3 12 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolynomial Division & Manipulation
TypeSketching Polynomial Curves
DifficultyModerate -0.3 This is a structured multi-part question covering standard C1 techniques: verifying a root by substitution, polynomial division, factorization, curve sketching, and solving a cubic equation. While it requires multiple steps, each part follows routine procedures with no novel problem-solving required, making it slightly easier than average for A-level.
Spec1.02f Solve quadratic equations: including in a function of unknown1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02k Simplify rational expressions: factorising, cancelling, algebraic division1.02n Sketch curves: simple equations including polynomials

3 You are given that \(\mathrm { f } ( x ) = x ^ { 3 } + 9 x ^ { 2 } + 20 x + 12\).
  1. Show that \(x = - 2\) is a root of \(\mathrm { f } ( x ) = 0\).
  2. Divide \(\mathrm { f } ( x )\) by \(x + 6\).
  3. Express \(\mathrm { f } ( x )\) in fully factorised form.
  4. Sketch the graph of \(y = \mathrm { f } ( x )\).
  5. Solve the equation \(\mathrm { f } ( x ) = 12\).

Question 3:
Part (i)
AnswerMarks Guidance
\(f(-2)\) usedM1 Or M1 for division by \((x+2)\) attempted
\(-8 + 36 - 40 + 12 = 0\)A1 As far as \(x^3 + 2x^2\) then A1 for \(x^2 + 7x + 6\) with no remainder
Part (ii)
AnswerMarks Guidance
Division attempted as far as \(x^2 + 3x\)M1 Or inspection with \(b=3\) or \(c=2\) found
\(x^2 + 3x + 2\) or \((x+2)(x+1)\)A1 B2 for correct answer
Part (iii)
AnswerMarks Guidance
\((x+2)(x+6)(x+1)\)2 Allow seen earlier; M1 for \((x+2)(x+1)\)
Part (iv)
AnswerMarks Guidance
Sketch of cubic the right way upG1 With 2 turning pts; no 3rd tp
Through 12 marked on \(y\) axisG1 Curve must extend to \(x > 0\)
Intercepts \(-6, -2, -1\) on \(x\) axisG1 Condone no graph for \(x < -6\)
Part (v)
AnswerMarks Guidance
\([x](x^2 + 9x + 20)\)M1 Or other partial factorisation
\([x](x+4)(x+5)\)M1
\(x = 0, -4, -5\)A1 Or B1 for each root found e.g. using factor theorem
## Question 3:

### Part (i)
| $f(-2)$ used | M1 | Or M1 for division by $(x+2)$ attempted |
|---|---|---|
| $-8 + 36 - 40 + 12 = 0$ | A1 | As far as $x^3 + 2x^2$ then A1 for $x^2 + 7x + 6$ with no remainder |

### Part (ii)
| Division attempted as far as $x^2 + 3x$ | M1 | Or inspection with $b=3$ or $c=2$ found |
|---|---|---|
| $x^2 + 3x + 2$ or $(x+2)(x+1)$ | A1 | B2 for correct answer |

### Part (iii)
| $(x+2)(x+6)(x+1)$ | 2 | Allow seen earlier; M1 for $(x+2)(x+1)$ |

### Part (iv)
| Sketch of cubic the right way up | G1 | With 2 turning pts; no 3rd tp |
|---|---|---|
| Through 12 marked on $y$ axis | G1 | Curve must extend to $x > 0$ |
| Intercepts $-6, -2, -1$ on $x$ axis | G1 | Condone no graph for $x < -6$ |

### Part (v)
| $[x](x^2 + 9x + 20)$ | M1 | Or other partial factorisation |
|---|---|---|
| $[x](x+4)(x+5)$ | M1 | |
| $x = 0, -4, -5$ | A1 | Or B1 for each root found e.g. using factor theorem |

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3 You are given that $\mathrm { f } ( x ) = x ^ { 3 } + 9 x ^ { 2 } + 20 x + 12$.\\
(i) Show that $x = - 2$ is a root of $\mathrm { f } ( x ) = 0$.\\
(ii) Divide $\mathrm { f } ( x )$ by $x + 6$.\\
(iii) Express $\mathrm { f } ( x )$ in fully factorised form.\\
(iv) Sketch the graph of $y = \mathrm { f } ( x )$.\\
(v) Solve the equation $\mathrm { f } ( x ) = 12$.

\hfill \mbox{\textit{OCR MEI C1  Q3 [12]}}