Easy -1.8 This is a straightforward linear inequality requiring only basic algebraic manipulation: multiply through by 7, collect like terms, and divide. It's a routine C1 exercise with no conceptual challenges, making it significantly easier than average A-level questions.
For correctly multiplying by 7 to eliminate the fraction, including expanding bracket if this step done first; may be earned later; first two Ms may be earned with an equation or wrong inequality
\(-12 > 10x\) or \(-10x > 12\) or ft
M1
For correctly collecting \(x\) terms on one side and number terms on the other and simplifying; ft wrong first step
\(x < -\frac{12}{10}\) or \(-\frac{12}{10} > x\) oe isw or ft
M1
ft their \(ax\) [inequality] \(b\), where \(b \neq 0\) and \(a \neq 0\) or \(\pm 1\); award 3 marks only if correct answer obtained after equations or inequalities are used with no errors
## Question 4:
| Answer | Marks | Guidance |
|--------|-------|----------|
| $4x - 5 > 14x + 7$ | M1 | For correctly multiplying by 7 to eliminate the fraction, including expanding bracket if this step done first; may be earned later; first two Ms may be earned with an equation or wrong inequality |
| $-12 > 10x$ or $-10x > 12$ or ft | M1 | For correctly collecting $x$ terms on one side and number terms on the other and simplifying; ft wrong first step |
| $x < -\frac{12}{10}$ or $-\frac{12}{10} > x$ oe isw or ft | M1 | ft their $ax$ [inequality] $b$, where $b \neq 0$ and $a \neq 0$ or $\pm 1$; award 3 marks only if correct answer obtained after equations or inequalities are used with no errors |