CAIE P2 2024 June — Question 7 9 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2024
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolynomial Division & Manipulation
TypeFinding Constants from Integration After Division
DifficultyStandard +0.3 This is a straightforward polynomial division question requiring standard algebraic manipulation and integration. Part (a) involves routine polynomial long division, while part (b) combines this with a definite integral that simplifies nicely. The question is slightly easier than average as it follows a predictable structure with clear signposting and standard techniques throughout.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.08j Integration using partial fractions

7 The polynomial \(\mathrm { p } ( x )\) is defined by $$p ( x ) = 9 x ^ { 3 } + 6 x ^ { 2 } + 12 x + k$$ where \(k\) is a constant.
  1. Find the quotient when \(\mathrm { p } ( x )\) is divided by \(( 3 x + 2 )\) and show that the remainder is \(( k - 8 )\).
  2. It is given that \(\int _ { 1 } ^ { 6 } \frac { \mathrm { p } ( \mathrm { x } ) } { 3 \mathrm { x } + 2 } \mathrm { dx } = \mathrm { a } + \ln 64\), where \(a\) is an integer. Find the values of \(a\) and \(k\).
    If you use the following page to complete the answer to any question, the question number must be clearly shown.

Question 7(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Carry out division at least as far as \(3x^2 + n_1\)M1 Or equivalent (inspection, …)
Obtain quotient \(3x^2 + 4\)A1
Confirm remainder is \(k - 8\)A1 Answer given – necessary detail needed. SC B1 for correct use of factor theorem to show remainder is \(k-8\)
Alternative Method (Synthetic Division):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Synthetic division with \(-\frac{2}{3}\): row entries \(9, 6, 12, k\) then \(-6, 0, -8\) giving \(9, 0, 12, k-8\)(M1) Allow one sign error
Obtain quotient \(3x^2 + 4\)(A1)
Confirm remainder is \(k - 8\)(A1)
Total3
Question 7(b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Integrate to obtain at least a term in \(x^3\) and term of form \(n_2\ln(3x+2)\)\*M1 Need to be using *their* answer to part (a)
Obtain \(x^3 + 4x + \frac{1}{3}(k-8)\ln(3x+2)\)A1 FT on a quotient of \(9x^2 + 12\)
Apply limits correctly to expression with three termsDM1
Obtain \(a = 235\)A1 FT on a quotient of \(9x^2 + 12\)
Equate logarithm term to \(\ln 64\) and apply appropriate logarithm propertiesDM1
Obtain \(k = 17\)A1
Total6 SC 2 marks for use of quotient \(3x^2+4\) or \(9x^2+12\) to obtain either 235 or 705 if no other marks are available
## Question 7(a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Carry out division at least as far as $3x^2 + n_1$ | M1 | Or equivalent (inspection, …) |
| Obtain quotient $3x^2 + 4$ | A1 | |
| Confirm remainder is $k - 8$ | A1 | Answer given – necessary detail needed. SC B1 for correct use of factor theorem to show remainder is $k-8$ |

**Alternative Method (Synthetic Division):**

| Answer/Working | Mark | Guidance |
|---|---|---|
| Synthetic division with $-\frac{2}{3}$: row entries $9, 6, 12, k$ then $-6, 0, -8$ giving $9, 0, 12, k-8$ | (M1) | Allow one sign error |
| Obtain quotient $3x^2 + 4$ | (A1) | |
| Confirm remainder is $k - 8$ | (A1) | |
| **Total** | **3** | |

---

## Question 7(b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Integrate to obtain at least a term in $x^3$ and term of form $n_2\ln(3x+2)$ | \*M1 | Need to be using *their* answer to part (a) |
| Obtain $x^3 + 4x + \frac{1}{3}(k-8)\ln(3x+2)$ | A1 | FT on a quotient of $9x^2 + 12$ |
| Apply limits correctly to expression with three terms | DM1 | |
| Obtain $a = 235$ | A1 | FT on a quotient of $9x^2 + 12$ |
| Equate logarithm term to $\ln 64$ and apply appropriate logarithm properties | DM1 | |
| Obtain $k = 17$ | A1 | |
| **Total** | **6** | SC 2 marks for use of quotient $3x^2+4$ or $9x^2+12$ to obtain either 235 or 705 if no other marks are available |
7 The polynomial $\mathrm { p } ( x )$ is defined by

$$p ( x ) = 9 x ^ { 3 } + 6 x ^ { 2 } + 12 x + k$$

where $k$ is a constant.
\begin{enumerate}[label=(\alph*)]
\item Find the quotient when $\mathrm { p } ( x )$ is divided by $( 3 x + 2 )$ and show that the remainder is $( k - 8 )$.
\item It is given that $\int _ { 1 } ^ { 6 } \frac { \mathrm { p } ( \mathrm { x } ) } { 3 \mathrm { x } + 2 } \mathrm { dx } = \mathrm { a } + \ln 64$, where $a$ is an integer.

Find the values of $a$ and $k$.\\

If you use the following page to complete the answer to any question, the question number must be clearly shown.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2024 Q7 [9]}}