CAIE P2 2024 June — Question 3 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2024
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSketch modulus of linear and non-modulus linear, find intersection
DifficultyStandard +0.3 Part (a) is routine sketching of a V-shaped modulus graph and a linear function. Part (b) requires standard technique of splitting into cases or squaring, yielding a straightforward inequality. Part (c) adds a mild substitution step (x = e^{0.1N}) and taking logarithms, but follows directly from part (b). Overall slightly easier than average due to structured scaffolding and standard methods.
Spec1.02l Modulus function: notation, relations, equations and inequalities1.02s Modulus graphs: sketch graph of |ax+b|1.06a Exponential function: a^x and e^x graphs and properties

3
  1. Sketch on the same diagram the graphs of \(y = | 3 x - 8 |\) and \(y = 5 - x\).
  2. Solve the inequality \(| 3 x - 8 | < 5 - x\).
  3. Hence determine the largest integer \(N\) satisfying the inequality \(\left| 3 e ^ { 0.1 N } - 8 \right| < 5 - e ^ { 0.1 N }\).

Question 3(a):
AnswerMarks Guidance
AnswerMarks Guidance
Draw V-shaped graph with vertex on positive \(x\)-axis in the first quadrantB1
Draw correct graph of \(y = 5 - x\) correctly positioned with respect to modulus graphB1 Two points of intersection
Question 3(b):
AnswerMarks Guidance
AnswerMarks Guidance
Solve \(3x - 8 = 5 - x\) to obtain \(\frac{13}{4}\)B1 Or inequality
Solve linear equation or inequality with signs of \(3x\) and \(x\) the sameM1
Obtain \(\frac{3}{2}\)A1
Conclude \(\frac{3}{2} < x < \frac{13}{4}\) or \(x > \frac{3}{2}\) and \(x < \frac{13}{4}\)A1 Allow alternative notation e.g. \(\left(\frac{3}{2}, \frac{13}{4}\right)\)
Alternative Method:
AnswerMarks Guidance
AnswerMarks Guidance
State or imply \((3x-8)^2 = (5-x)^2\)(B1)
Attempt solution of three-term equation (or inequality)(M1)
Obtain \(\frac{3}{2}\) and \(\frac{13}{4}\)(A1)
Conclude \(\frac{3}{2} < x < \frac{13}{4}\) or \(x > \frac{3}{2}\) and \(x < \frac{13}{4}\)(A1) Allow alternative notation e.g. \(\left(\frac{3}{2}, \frac{13}{4}\right)\)
Question 3(c):
AnswerMarks Guidance
AnswerMarks Guidance
Attempt value of \(N\) (maybe non-integer) for \(e^{0.1N} < \textit{their } \frac{13}{4}\)M1 Allow \(e^{0.1N} = \textit{their } \frac{13}{4}\) (or inequality)
Conclude with single integer 11A1
## Question 3(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Draw V-shaped graph with vertex on positive $x$-axis in the first quadrant | B1 | |
| Draw correct graph of $y = 5 - x$ correctly positioned with respect to modulus graph | B1 | Two points of intersection |

## Question 3(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Solve $3x - 8 = 5 - x$ to obtain $\frac{13}{4}$ | B1 | Or inequality |
| Solve linear equation or inequality with signs of $3x$ and $x$ the same | M1 | |
| Obtain $\frac{3}{2}$ | A1 | |
| Conclude $\frac{3}{2} < x < \frac{13}{4}$ or $x > \frac{3}{2}$ **and** $x < \frac{13}{4}$ | A1 | Allow alternative notation e.g. $\left(\frac{3}{2}, \frac{13}{4}\right)$ |

**Alternative Method:**

| Answer | Marks | Guidance |
|--------|-------|----------|
| State or imply $(3x-8)^2 = (5-x)^2$ | (B1) | |
| Attempt solution of three-term equation (or inequality) | (M1) | |
| Obtain $\frac{3}{2}$ and $\frac{13}{4}$ | (A1) | |
| Conclude $\frac{3}{2} < x < \frac{13}{4}$ or $x > \frac{3}{2}$ **and** $x < \frac{13}{4}$ | (A1) | Allow alternative notation e.g. $\left(\frac{3}{2}, \frac{13}{4}\right)$ |

## Question 3(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Attempt value of $N$ (maybe non-integer) for $e^{0.1N} < \textit{their } \frac{13}{4}$ | M1 | Allow $e^{0.1N} = \textit{their } \frac{13}{4}$ (or inequality) |
| Conclude with single integer 11 | A1 | |

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3
\begin{enumerate}[label=(\alph*)]
\item Sketch on the same diagram the graphs of $y = | 3 x - 8 |$ and $y = 5 - x$.
\item Solve the inequality $| 3 x - 8 | < 5 - x$.
\item Hence determine the largest integer $N$ satisfying the inequality $\left| 3 e ^ { 0.1 N } - 8 \right| < 5 - e ^ { 0.1 N }$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2024 Q3 [8]}}