OCR C1 2005 January — Question 8 8 marks

Exam BoardOCR
ModuleC1 (Core Mathematics 1)
Year2005
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypePerimeter or area constraint inequality
DifficultyModerate -0.8 This is a straightforward application question requiring translation of word problems into inequalities and basic algebraic manipulation. Part (i) is simple linear inequality setup, part (ii) involves expanding and factorizing a quadratic (with the factorization given), and part (iii) requires solving linear and quadratic inequalities—all standard C1 techniques with no novel problem-solving required.
Spec1.02g Inequalities: linear and quadratic in single variable1.02h Express solutions: using 'and', 'or', set and interval notation

8 The length of a rectangular children's playground is 10 m more than its width. The width of the playground is \(x\) metres.
  1. The perimeter of the playground is greater than 64 m . Write down a linear inequality in \(x\).
  2. The area of the playground is less than \(299 \mathrm {~m} ^ { 2 }\). Show that \(( x - 13 ) ( x + 23 ) < 0\).
  3. By solving the inequalities in parts (i) and (ii), determine the set of possible values of \(x\).

AnswerMarks Guidance
(i)Marks Guidance
\(2[10 + x + x] > 64\)B1 1 \(20 + 4x > 64\) o.e.
(ii)Marks Guidance
\(x(x+10) < 299\)B1
\(x^2 + 10x - 299 < 0\)
\((x-13)(x+23) < 0\)B1 2 Correctly shows \((x-13)(x+23) < 0\)
(iii)Marks Guidance
\(x > 11\)B1 \(\sqrt{--}\) \(x > 11\) ft from their (i)
\((x-13)(x+23) < 0\)M2 Correct method to solve \((x-13)(x+23) < 0\) eg graph
\(-23 < x < 13\)A1 \(-23 < x < 13\) seen in this form or as number line
SR if seen with no working B1
\(\therefore 11 < x < 13\)B1 5
8
**(i)** | **Marks** | **Guidance**
---|---|---
$2[10 + x + x] > 64$ | B1 1 | $20 + 4x > 64$ o.e.

**(ii)** | **Marks** | **Guidance**
---|---|---
$x(x+10) < 299$ | B1 | 
$x^2 + 10x - 299 < 0$ | | 
$(x-13)(x+23) < 0$ | B1 2 | Correctly shows $(x-13)(x+23) < 0$ | **AG**

**(iii)** | **Marks** | **Guidance**
---|---|---
$x > 11$ | B1 $\sqrt{--}$ | $x > 11$ ft from their (i)
$(x-13)(x+23) < 0$ | M2 | Correct method to solve $(x-13)(x+23) < 0$ eg graph
 | | 
$-23 < x < 13$ | A1 | $-23 < x < 13$ seen in this form or as number line
 | | **SR** if seen with no working B1
$\therefore 11 < x < 13$ | B1 5 | 
| **8** |
8 The length of a rectangular children's playground is 10 m more than its width. The width of the playground is $x$ metres.\\
(i) The perimeter of the playground is greater than 64 m . Write down a linear inequality in $x$.\\
(ii) The area of the playground is less than $299 \mathrm {~m} ^ { 2 }$. Show that $( x - 13 ) ( x + 23 ) < 0$.\\
(iii) By solving the inequalities in parts (i) and (ii), determine the set of possible values of $x$.

\hfill \mbox{\textit{OCR C1 2005 Q8 [8]}}