OCR C1 2005 January — Question 6 7 marks

Exam BoardOCR
ModuleC1 (Core Mathematics 1)
Year2005
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscriminant and conditions for roots
TypeFind discriminant, state roots
DifficultyModerate -0.8 Part (i) is direct application of the discriminant formula b²-4ac with straightforward arithmetic, requiring only recall of the relationship between discriminant and number of roots. Part (ii) uses the equal roots condition (discriminant = 0) leading to a simple equation to solve for p. Both parts are routine textbook exercises with no problem-solving insight required, making this easier than average.
Spec1.02d Quadratic functions: graphs and discriminant conditions

6
  1. Calculate the discriminant of \(- 2 x ^ { 2 } + 7 x + 3\) and hence state the number of real roots of the equation \(- 2 x ^ { 2 } + 7 x + 3 = 0\).
  2. The quadratic equation \(2 x ^ { 2 } + ( p + 1 ) x + 8 = 0\) has equal roots. Find the possible values of \(p\).

AnswerMarks Guidance
(i)Marks Guidance
\(49 - 4 \times (-2) \times 3 = 73\)M1 Uses \(b^2 - 4ac\)
2 real rootsA1
B1 \(\sqrt{3}\)2 real roots (ft from their value)
Attempts \(b^2 - 4ac = 0\) (involving p) or attempts to complete square (involving p)
(ii)Marks Guidance
\((p+1)^2 - 64 = 0\) or \(2[(x + \frac{p+1}{4})^2 - \frac{(p+1)^2}{16} + 4] = 0\)M1
A1\((p+1)^2 - 64 = 0\) aef
\(p = -9, 7\)B1 \(p = -9\)
B1 4\(p = 7\)
7
**(i)** | **Marks** | **Guidance**
---|---|---
$49 - 4 \times (-2) \times 3 = 73$ | M1 | Uses $b^2 - 4ac$
2 real roots | A1 | 
 | B1 $\sqrt{3}$ | 2 real roots (ft from their value)
 | | Attempts $b^2 - 4ac = 0$ (involving p) or attempts to complete square (involving p)

**(ii)** | **Marks** | **Guidance**
---|---|---
$(p+1)^2 - 64 = 0$ or $2[(x + \frac{p+1}{4})^2 - \frac{(p+1)^2}{16} + 4] = 0$ | M1 | 
 | A1 | $(p+1)^2 - 64 = 0$ aef
$p = -9, 7$ | B1 | $p = -9$
 | B1 4 | $p = 7$
| **7** |
6 (i) Calculate the discriminant of $- 2 x ^ { 2 } + 7 x + 3$ and hence state the number of real roots of the equation $- 2 x ^ { 2 } + 7 x + 3 = 0$.\\
(ii) The quadratic equation $2 x ^ { 2 } + ( p + 1 ) x + 8 = 0$ has equal roots. Find the possible values of $p$.

\hfill \mbox{\textit{OCR C1 2005 Q6 [7]}}