Edexcel M1 2009 January — Question 3 9 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2009
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeCollision with two possible outcomes
DifficultyModerate -0.3 This is a straightforward M1 momentum conservation problem with clearly defined before/after states. Part (a) requires direct application of conservation of momentum, part (b) involves sign interpretation, and part (c) is a standard impulse calculation. While multi-part, each step follows routine mechanics procedures without requiring problem-solving insight or novel approaches.
Spec6.03a Linear momentum: p = mv6.03b Conservation of momentum: 1D two particles6.03e Impulse: by a force6.03f Impulse-momentum: relation

3. Two particles \(A\) and \(B\) are moving on a smooth horizontal plane. The mass of \(A\) is \(k m\), where \(2 < k < 3\), and the mass of \(B\) is \(m\). The particles are moving along the same straight line, but in opposite directions, and they collide directly. Immediately before they collide the speed of \(A\) is \(2 u\) and the speed of \(B\) is \(4 u\). As a result of the collision the speed of \(A\) is halved and its direction of motion is reversed.
  1. Find, in terms of \(k\) and \(u\), the speed of \(B\) immediately after the collision.
  2. State whether the direction of motion of \(B\) changes as a result of the collision, explaining your answer. Given that \(k = \frac { 7 } { 3 }\),
  3. find, in terms of \(m\) and \(u\), the magnitude of the impulse that \(A\) exerts on \(B\) in the collision.

Question 3:
Part (a):
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(2u \rightarrow \quad \leftarrow 4u \qquad km(2u) - 4mu = -kmu + mv\)M1 A1
\(u(3k - 4) = v\)A1 (3)
Part (b):
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(k > 2 \Rightarrow v > 0 \Rightarrow\) direction of motion reversedM1A1A1 cso (3)
Part (c):
AnswerMarks Guidance
Working/AnswerMarks Guidance
For \(B\): \(m(u(3k-4)) - (-4u)\)M1 A1 f.t.
\(= 7mu\)A1 (3) [9]
## Question 3:

### Part (a):
| Working/Answer | Marks | Guidance |
|---|---|---|
| $2u \rightarrow \quad \leftarrow 4u \qquad km(2u) - 4mu = -kmu + mv$ | M1 A1 | |
| $u(3k - 4) = v$ | A1 | **(3)** |

### Part (b):
| Working/Answer | Marks | Guidance |
|---|---|---|
| $k > 2 \Rightarrow v > 0 \Rightarrow$ direction of motion reversed | M1A1A1 cso | **(3)** |

### Part (c):
| Working/Answer | Marks | Guidance |
|---|---|---|
| For $B$: $m(u(3k-4)) - (-4u)$ | M1 A1 f.t. | |
| $= 7mu$ | A1 | **(3) [9]** |

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3. Two particles $A$ and $B$ are moving on a smooth horizontal plane. The mass of $A$ is $k m$, where $2 < k < 3$, and the mass of $B$ is $m$. The particles are moving along the same straight line, but in opposite directions, and they collide directly. Immediately before they collide the speed of $A$ is $2 u$ and the speed of $B$ is $4 u$. As a result of the collision the speed of $A$ is halved and its direction of motion is reversed.
\begin{enumerate}[label=(\alph*)]
\item Find, in terms of $k$ and $u$, the speed of $B$ immediately after the collision.
\item State whether the direction of motion of $B$ changes as a result of the collision, explaining your answer.

Given that $k = \frac { 7 } { 3 }$,
\item find, in terms of $m$ and $u$, the magnitude of the impulse that $A$ exerts on $B$ in the collision.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1 2009 Q3 [9]}}