CAIE P1 Specimen — Question 5 8 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
SessionSpecimen
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProduct & Quotient Rules
TypeFind stationary points and nature
DifficultyModerate -0.8 This is a straightforward stationary points question using basic differentiation rules (power rule for x^{-1} and x). Finding derivatives, solving dy/dx=0, and using the second derivative test are all standard P1 procedures with no conceptual challenges or multi-step problem-solving required.
Spec1.07d Second derivatives: d^2y/dx^2 notation1.07i Differentiate x^n: for rational n and sums1.07n Stationary points: find maxima, minima using derivatives

5 A curve has equation \(y = \frac { 8 } { x } + 2 x\).
  1. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) and \(\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } }\).
  2. Find the coordinates of the stationary points and state, with a reason, the nature of each stationary point.

Question 5(i):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{dy}{dx} = -\frac{8}{x^2} + 2\) caoB1B1
\(\frac{d^2y}{dx^2} = \frac{16}{x^3}\) caoB1
Total: 3
Question 5(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(-\frac{8}{x^2} + 2 = 0 \rightarrow 2x^2 - 8 = 0\)M1 Set \(= 0\) and rearrange to quadratic form
\(x = \pm 2\)A1
\(y = \pm 8\)A1 If A0A0 scored, SCA1 for just \((2, 8)\)
\(\frac{d^2y}{dx^2} > 0\) when \(x = 2\) hence MINIMUMB1\(\sqrt{}\) Ft for "correct" conclusion if \(\frac{d^2y}{dx^2}\) incorrect or any valid method inc. a good sketch
\(\frac{d^2y}{dx^2} < 0\) when \(x = -2\) hence MAXIMUMB1\(\sqrt{}\)
Total: 5
## Question 5(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{dy}{dx} = -\frac{8}{x^2} + 2$ cao | B1B1 | |
| $\frac{d^2y}{dx^2} = \frac{16}{x^3}$ cao | B1 | |
| **Total: 3** | | |

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## Question 5(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $-\frac{8}{x^2} + 2 = 0 \rightarrow 2x^2 - 8 = 0$ | M1 | Set $= 0$ and rearrange to quadratic form |
| $x = \pm 2$ | A1 | |
| $y = \pm 8$ | A1 | If A0A0 scored, SCA1 for just $(2, 8)$ |
| $\frac{d^2y}{dx^2} > 0$ when $x = 2$ hence MINIMUM | B1$\sqrt{}$ | Ft for "correct" conclusion if $\frac{d^2y}{dx^2}$ incorrect or any valid method inc. a good sketch |
| $\frac{d^2y}{dx^2} < 0$ when $x = -2$ hence MAXIMUM | B1$\sqrt{}$ | |
| **Total: 5** | | |

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5 A curve has equation $y = \frac { 8 } { x } + 2 x$.\\
(i) Find $\frac { \mathrm { d } y } { \mathrm {~d} x }$ and $\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } }$.\\

(ii) Find the coordinates of the stationary points and state, with a reason, the nature of each stationary point.\\

\hfill \mbox{\textit{CAIE P1  Q5 [8]}}