| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2003 |
| Session | June |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Momentum and Collisions |
| Type | Given impulse, find velocity or mass |
| Difficulty | Easy -1.3 This is a straightforward M1 mechanics question requiring direct application of impulse-momentum theorem (part a) and conservation of momentum (part b), followed by another impulse calculation (part c). All steps are routine with no problem-solving insight needed—just plug values into standard formulas. |
| Spec | 6.03b Conservation of momentum: 1D two particles6.03f Impulse-momentum: relation |
2. Two particles $A$ and $B$ have mass 0.12 kg and 0.08 kg respectively. They are initially at rest on a smooth horizontal table. Particle $A$ is then given an impulse in the direction $A B$ so that it moves with speed $3 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ directly towards $B$.
\begin{enumerate}[label=(\alph*)]
\item Find the magnitude of this impulse, stating clearly the units in which your answer is given.\\
(2)
Immediately after the particles collide, the speed of $A$ is $1.2 \mathrm {~m} \mathrm {~s} ^ { - 1 }$, its direction of motion being unchanged.
\item Find the speed of $B$ immediately after the collision.
\item Find the magnitude of the impulse exerted on $A$ in the collision.
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2003 Q2 [7]}}