Edexcel M1 2011 January — Question 1 5 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2011
SessionJanuary
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeDirect collision, find impulse magnitude
DifficultyModerate -0.8 This is a straightforward M1 collision problem requiring direct application of conservation of momentum to find m, then using the impulse-momentum theorem (impulse = change in momentum). Both parts involve standard formulas with clear given values and minimal algebraic manipulation—easier than average A-level maths questions.
Spec6.03b Conservation of momentum: 1D two particles6.03f Impulse-momentum: relation

  1. Two particles \(B\) and \(C\) have mass \(m \mathrm {~kg}\) and 3 kg respectively. They are moving towards each other in opposite directions on a smooth horizontal table. The two particles collide directly. Immediately before the collision, the speed of \(B\) is \(4 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) and the speed of \(C\) is \(2 \mathrm {~m} \mathrm {~s} ^ { - 1 }\). In the collision the direction of motion of \(C\) is reversed and the direction of motion of \(B\) is unchanged. Immediately after the collision, the speed of \(B\) is \(1 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) and the speed of \(C\) is \(3 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
Find
  1. the value of \(m\),
  2. the magnitude of the impulse received by \(C\).

AnswerMarks Guidance
PartAnswer/Working Marks
(a)Conservation of momentum: \(4m - 6 = m + 9\) → \(m = 5\) M1 A1 A1
(b)Impulse = change in momentum = \(3 \times 3 - (3 \times -2) = 15\) M1 A1
[5 marks total]
| **Part** | **Answer/Working** | **Marks** | **Guidance** |
|----------|-------------------|----------|-------------|
| (a) | Conservation of momentum: $4m - 6 = m + 9$ → $m = 5$ | M1 A1 A1 | (3 marks) |
| (b) | Impulse = change in momentum = $3 \times 3 - (3 \times -2) = 15$ | M1 A1 | (2 marks) |
| | | | **[5 marks total]** |
\begin{enumerate}
  \item Two particles $B$ and $C$ have mass $m \mathrm {~kg}$ and 3 kg respectively. They are moving towards each other in opposite directions on a smooth horizontal table. The two particles collide directly. Immediately before the collision, the speed of $B$ is $4 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ and the speed of $C$ is $2 \mathrm {~m} \mathrm {~s} ^ { - 1 }$. In the collision the direction of motion of $C$ is reversed and the direction of motion of $B$ is unchanged. Immediately after the collision, the speed of $B$ is $1 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ and the speed of $C$ is $3 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\end{enumerate}

Find\\
(a) the value of $m$,\\
(b) the magnitude of the impulse received by $C$.\\

\hfill \mbox{\textit{Edexcel M1 2011 Q1 [5]}}