| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2011 |
| Session | January |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | SUVAT in 2D & Gravity |
| Type | Vertical projection: speed of projection |
| Difficulty | Moderate -0.3 This is a straightforward SUVAT problem with standard vertical motion under gravity. Part (a) uses v = u + at with given values, part (b) applies v² = u² + 2as at maximum height, and part (c) uses s = ut + ½at². All three parts follow routine mechanics procedures with no conceptual challenges, making it slightly easier than average but still requiring correct application of multiple equations. |
| Spec | 3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form |
| Answer | Marks | Guidance |
|---|---|---|
| Part | Answer/Working | Marks |
| (a) | \(-6.45 = u - 9.8 \times 0.75\) → \(0.9 = u\) (marked as **) | M1 A1 A1 |
| (b) | \(0 = 0.81 - 2 \times 9.8 \times s\) → \(s = 0.041\) or \(0.0413\) | M1 A1 |
| (c) | \(h = -0.9 \times 0.75 + 4.9 \times 0.75^2\) → \(h = 2.1\) or \(2.08\) | M1 A1 A1 |
| [8 marks total] |
| **Part** | **Answer/Working** | **Marks** | **Guidance** |
|----------|-------------------|----------|-------------|
| (a) | $-6.45 = u - 9.8 \times 0.75$ → $0.9 = u$ (marked as **) | M1 A1 A1 | (3 marks) |
| (b) | $0 = 0.81 - 2 \times 9.8 \times s$ → $s = 0.041$ or $0.0413$ | M1 A1 | (2 marks) |
| (c) | $h = -0.9 \times 0.75 + 4.9 \times 0.75^2$ → $h = 2.1$ or $2.08$ | M1 A1 A1 | (3 marks) |
| | | | **[8 marks total]** |2. A ball is thrown vertically upwards with speed $u \mathrm {~m} \mathrm {~s} ^ { - 1 }$ from a point $P$ at height $h$ metres above the ground. The ball hits the ground 0.75 s later. The speed of the ball immediately before it hits the ground is $6.45 \mathrm {~m} \mathrm {~s} ^ { - 1 }$. The ball is modelled as a particle.
\begin{enumerate}[label=(\alph*)]
\item Show that $u = 0.9$
\item Find the height above $P$ to which the ball rises before it starts to fall towards the ground again.
\item Find the value of $h$.
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2011 Q2 [8]}}