Edexcel FP1 — Question 4 9 marks

Exam BoardEdexcel
ModuleFP1 (Further Pure Mathematics 1)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNewton-Raphson method
TypeCompare Newton-Raphson with linear interpolation
DifficultyModerate -0.3 This is a straightforward application of two standard numerical methods (linear interpolation and Newton-Raphson) with clear instructions and simple arithmetic. While it's Further Maths content, both procedures are routine calculations requiring only substitution into formulas with no problem-solving insight needed.
Spec1.09a Sign change methods: locate roots1.09d Newton-Raphson method

4. \(f ( x ) = x ^ { 3 } - 4 x ^ { 2 } + 5 x - 3\) The equation \(\mathrm { f } ( x ) = 0\) has a root \(\alpha\) in the interval ( 2,3 ).
  1. Use linear interpolation on the end points of this interval to obtain an approximation for \(\alpha\).
  2. Taking 2.5 as a first approximation to \(\alpha\), apply the Newton - Raphson procedure once to \(\mathrm { f } ( x )\) to obtain a second approximation to \(\alpha\). Give your answer to 2 decimal places.

4. $f ( x ) = x ^ { 3 } - 4 x ^ { 2 } + 5 x - 3$

The equation $\mathrm { f } ( x ) = 0$ has a root $\alpha$ in the interval ( 2,3 ).
\begin{enumerate}[label=(\alph*)]
\item Use linear interpolation on the end points of this interval to obtain an approximation for $\alpha$.
\item Taking 2.5 as a first approximation to $\alpha$, apply the Newton - Raphson procedure once to $\mathrm { f } ( x )$ to obtain a second approximation to $\alpha$. Give your answer to 2 decimal places.
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP1  Q4 [9]}}