Edexcel FP1 2014 June — Question 3 6 marks

Exam BoardEdexcel
ModuleFP1 (Further Pure Mathematics 1)
Year2014
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear transformations
TypeArea scale factor from determinant
DifficultyModerate -0.3 Part (i)(a) requires recognizing a standard rotation matrix with cos(45°) and sin(45°) values—straightforward pattern matching. Part (i)(b) is trivial recall. Part (ii) uses the determinant-area relationship (area scales by |det M|), requiring one calculation: |det M| = 224/16 = 14, so 9+2k = 14, giving k = 2.5. This is a standard FP1 question testing basic matrix transformation concepts with minimal problem-solving, slightly easier than average A-level due to its routine nature.
Spec4.03d Linear transformations 2D: reflection, rotation, enlargement, shear4.03h Determinant 2x2: calculation

3. (i) $$\mathbf { A } = \left( \begin{array} { c c } \frac { 1 } { \sqrt { } 2 } & \frac { - 1 } { \sqrt { } 2 } \\ \frac { 1 } { \sqrt { } 2 } & \frac { 1 } { \sqrt { } 2 } \end{array} \right)$$
  1. Describe fully the single transformation represented by the matrix \(\mathbf { A }\). The matrix \(\mathbf { B }\) represents an enlargement, scale factor - 2 , with centre the origin.
  2. Write down the matrix \(\mathbf { B }\).
    (ii) $$\mathbf { M } = \left( \begin{array} { c c } 3 & k \\ - 2 & 3 \end{array} \right) , \quad \text { where } k \text { is a positive constant. }$$ Triangle \(T\) has an area of 16 square units. Triangle \(T\) is transformed onto the triangle \(T ^ { \prime }\) by the transformation represented by the matrix M. Given that the area of the triangle \(T ^ { \prime }\) is 224 square units, find the value of \(k\).

Question 3:
Part (i)(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Rotation of 45 degrees anticlockwise, about the originB1B1 B1: Rotation about \((0,0)\); B1: 45 degrees (anticlockwise). -45 or clockwise award B0
Part (i)(b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\begin{pmatrix} -2 & 0 \\ 0 & -2 \end{pmatrix}\)B1 Correct matrix
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\frac{224}{16} (= 14)\)B1 Correct area scale factor. Allow \(\pm 14\)
\(\det \mathbf{M} = 3 \times 3 - k \times -2 = 14\)M1 Attempt determinant and set equal to their area scale factor. Accept \(\det \mathbf{M} = 3 \times 3 \pm 2k\) only
\(k = 2.5\)A1 oe
## Question 3:

### Part (i)(a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Rotation of 45 degrees anticlockwise, about the origin | B1B1 | B1: Rotation about $(0,0)$; B1: 45 degrees (anticlockwise). -45 or clockwise award B0 |

### Part (i)(b):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\begin{pmatrix} -2 & 0 \\ 0 & -2 \end{pmatrix}$ | B1 | Correct matrix |

### Part (ii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\frac{224}{16} (= 14)$ | B1 | Correct area scale factor. Allow $\pm 14$ |
| $\det \mathbf{M} = 3 \times 3 - k \times -2 = 14$ | M1 | Attempt determinant and set equal to their area scale factor. Accept $\det \mathbf{M} = 3 \times 3 \pm 2k$ only |
| $k = 2.5$ | A1 | oe |

---
3. (i)

$$\mathbf { A } = \left( \begin{array} { c c } 
\frac { 1 } { \sqrt { } 2 } & \frac { - 1 } { \sqrt { } 2 } \\
\frac { 1 } { \sqrt { } 2 } & \frac { 1 } { \sqrt { } 2 }
\end{array} \right)$$
\begin{enumerate}[label=(\alph*)]
\item Describe fully the single transformation represented by the matrix $\mathbf { A }$.

The matrix $\mathbf { B }$ represents an enlargement, scale factor - 2 , with centre the origin.
\item Write down the matrix $\mathbf { B }$.\\
(ii)

$$\mathbf { M } = \left( \begin{array} { c c } 
3 & k \\
- 2 & 3
\end{array} \right) , \quad \text { where } k \text { is a positive constant. }$$

Triangle $T$ has an area of 16 square units.

Triangle $T$ is transformed onto the triangle $T ^ { \prime }$ by the transformation represented by the matrix M.

Given that the area of the triangle $T ^ { \prime }$ is 224 square units, find the value of $k$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP1 2014 Q3 [6]}}