Edexcel FP1 2009 June — Question 3 7 marks

Exam BoardEdexcel
ModuleFP1 (Further Pure Mathematics 1)
Year2009
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Arithmetic
TypeFactored form to roots
DifficultyModerate -0.8 This is a straightforward FP1 question requiring only direct application of the quadratic formula to two simple quadratics to find complex roots, followed by basic addition. Part (a) involves routine factorization and solving x²=-4 and completing the square or using the formula for x²+8x+25=0. Part (b) is trivial using either direct addition or Vieta's formulas. No problem-solving or insight required beyond standard techniques.
Spec4.02g Conjugate pairs: real coefficient polynomials4.05a Roots and coefficients: symmetric functions

3. $$f ( x ) = \left( x ^ { 2 } + 4 \right) \left( x ^ { 2 } + 8 x + 25 \right)$$
  1. Find the four roots of \(\mathrm { f } ( x ) = 0\).
  2. Find the sum of these four roots.

Question 3:
Part (a)
AnswerMarks Guidance
Working/AnswerMarks Notes
\(x^2 + 4 = 0 \Rightarrow x = ki,\quad x = \pm 2i\)M1, A1 Just \(x = 2i\) is M1 A0; \(x = \pm 2\) is M0A0
Solving 3-term quadratic: \(x = \frac{-8 \pm \sqrt{64-100}}{2} = -4+3i\) and \(-4-3i\)M1 M1 for solving quadratic following usual conventions
A1 A1ftA1 for correct root (simplified); A1ft for conjugate of first answer; accept correct answers with no working
Part (b)
AnswerMarks Guidance
Working/AnswerMarks Notes
\(2i + (-2i) + (-4+3i) + (-4-3i) = -8\)M1 A1cso M1 for adding four roots of which at least two are complex conjugates and getting a real answer; A1 for \(-8\) following correct roots; if any incorrect working in (a) this A mark will be A0
Alternative: Expands \(f(x)\) as quartic and chooses \(\pm\) coefficient of \(x^3\); result \(-8\)M1, A1 cso
## Question 3:

### Part (a)

| Working/Answer | Marks | Notes |
|---|---|---|
| $x^2 + 4 = 0 \Rightarrow x = ki,\quad x = \pm 2i$ | M1, A1 | Just $x = 2i$ is M1 A0; $x = \pm 2$ is M0A0 |
| Solving 3-term quadratic: $x = \frac{-8 \pm \sqrt{64-100}}{2} = -4+3i$ and $-4-3i$ | M1 | M1 for solving quadratic following usual conventions |
| | A1 A1ft | A1 for correct root (simplified); A1ft for conjugate of first answer; accept correct answers with no working |

### Part (b)

| Working/Answer | Marks | Notes |
|---|---|---|
| $2i + (-2i) + (-4+3i) + (-4-3i) = -8$ | M1 A1cso | M1 for adding four roots of which at least two are complex conjugates and getting a real answer; A1 for $-8$ following correct roots; if any incorrect working in (a) this A mark will be A0 |
| Alternative: Expands $f(x)$ as quartic and chooses $\pm$ coefficient of $x^3$; result $-8$ | M1, A1 cso | |

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3.

$$f ( x ) = \left( x ^ { 2 } + 4 \right) \left( x ^ { 2 } + 8 x + 25 \right)$$
\begin{enumerate}[label=(\alph*)]
\item Find the four roots of $\mathrm { f } ( x ) = 0$.
\item Find the sum of these four roots.
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP1 2009 Q3 [7]}}