Edexcel FP1 2014 January — Question 1

Exam BoardEdexcel
ModuleFP1 (Further Pure Mathematics 1)
Year2014
SessionJanuary
TopicSign Change & Interval Methods
TypePure Interval Bisection Only
  1. \(\mathrm { f } ( x ) = 2 x - 5 \cos x , \quad\) where \(x\) is in radians.
    1. Show that the equation \(\mathrm { f } ( x ) = 0\) has a root \(\alpha\) in the interval \([ 1,1.4 ]\).
      [0pt]
    2. Starting with the interval [1,1.4], use interval bisection twice to find an interval of width 0.1 which contains \(\alpha\).
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