Edexcel FP1 2014 January — Question 4 5 marks

Exam BoardEdexcel
ModuleFP1 (Further Pure Mathematics 1)
Year2014
SessionJanuary
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNewton-Raphson method
TypeNewton-Raphson with complex derivative required
DifficultyStandard +0.3 This is a straightforward application of the Newton-Raphson formula requiring differentiation of a function with fractional and negative powers, then one iteration of the process. While the derivative involves multiple terms (x^{1/2} and x^{-2}), this is standard FP1 fare with no conceptual challenges—just careful algebraic manipulation and calculator work.
Spec1.07i Differentiate x^n: for rational n and sums1.09d Newton-Raphson method

4. $$f ( x ) = 2 x ^ { \frac { 1 } { 2 } } - \frac { 6 } { x ^ { 2 } } - 3 , \quad x > 0$$ A root \(\beta\) of the equation \(\mathrm { f } ( x ) = 0\) lies in the interval \([ 3,4 ]\).
Taking 3.5 as a first approximation to \(\beta\), apply the Newton-Raphson process once to \(\mathrm { f } ( x )\) to obtain a second approximation to \(\beta\). Give your answer to 3 decimal places.

AnswerMarks Guidance
\(f(x) = 2\sqrt{x} - \frac{6}{x^2} - 3\), \(x > 0\)
\(f'(x) = \pm\frac{1}{2}x^{-\frac{1}{2}} \text{ or } \pm\mu x^{-3}\) \(\{+ 0\}\)M1
Correct differentiationA1
\(f(3.5) = \text{awrt } 0.25\)B1
\(\{f'(3.5) = 0.8144058657...\}\)
\(\beta = 3.5 - \frac{"0.2518614684..."}{" 0.8144058657..."} = 3.1907420755...\)M1 Correct application of Newton-Raphson using their values
\(= 3.191\) (3dp)A1 cao
| $f(x) = 2\sqrt{x} - \frac{6}{x^2} - 3$, $x > 0$ | | |
| $f'(x) = \pm\frac{1}{2}x^{-\frac{1}{2}} \text{ or } \pm\mu x^{-3}$ $\{+ 0\}$ | M1 | |
| Correct differentiation | A1 | |
| $f(3.5) = \text{awrt } 0.25$ | B1 | |
| $\{f'(3.5) = 0.8144058657...\}$ | | |
| $\beta = 3.5 - \frac{"0.2518614684..."}{" 0.8144058657..."} = 3.1907420755...$ | M1 | Correct application of Newton-Raphson using their values |
| $= 3.191$ (3dp) | A1 cao | |

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4.

$$f ( x ) = 2 x ^ { \frac { 1 } { 2 } } - \frac { 6 } { x ^ { 2 } } - 3 , \quad x > 0$$

A root $\beta$ of the equation $\mathrm { f } ( x ) = 0$ lies in the interval $[ 3,4 ]$.\\
Taking 3.5 as a first approximation to $\beta$, apply the Newton-Raphson process once to $\mathrm { f } ( x )$ to obtain a second approximation to $\beta$. Give your answer to 3 decimal places.\\

\hfill \mbox{\textit{Edexcel FP1 2014 Q4 [5]}}