Edexcel FP1 2012 January — Question 1 7 marks

Exam BoardEdexcel
ModuleFP1 (Further Pure Mathematics 1)
Year2012
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Arithmetic
TypeModulus and argument with operations
DifficultyModerate -0.5 This is a straightforward FP1 complex numbers question testing basic operations: finding an argument of a simple complex number, multiplication, and division using conjugate method. All three parts are routine textbook exercises requiring standard techniques with no problem-solving insight. While it's Further Maths content, these are foundational FP1 skills, making it slightly easier than an average A-level question overall.
Spec4.02a Complex numbers: real/imaginary parts, modulus, argument4.02e Arithmetic of complex numbers: add, subtract, multiply, divide

  1. Given that \(z _ { 1 } = 1 - \mathrm { i }\),
    1. find \(\arg \left( z _ { 1 } \right)\).
    Given also that \(z _ { 2 } = 3 + 4 \mathrm { i }\), find, in the form \(a + \mathrm { i } b , a , b \in \mathbb { R }\),
  2. \(z _ { 1 } z _ { 2 }\),
  3. \(\frac { z _ { 2 } } { z _ { 1 } }\). In part (b) and part (c) you must show all your working clearly.

Question 1:
Part (a)
AnswerMarks Guidance
Answer/WorkingMark Guidance Notes
\(\arg z_1 = -\arctan(1)\)M1 \(-\arctan(1)\) or \(\arctan(1)\) or \(\arctan(-1)\)
\(= -\dfrac{\pi}{4}\)A1 or \(-45°\) or awrt \(-0.785\) (oe e.g. \(\dfrac{7\pi}{4}\))
Correct answer only 2/2(2)
Part (b)
AnswerMarks Guidance
Answer/WorkingMark Guidance Notes
\(z_1 z_2 = (1-i)(3+4i) = 3 - 3i + 4i - 4i^2\)M1 At least 3 correct terms (unsimplified)
\(= 7 + i\)A1 cao
(2)
Part (c)
AnswerMarks Guidance
Answer/WorkingMark Guidance Notes
\(\dfrac{z_2}{z_1} = \dfrac{(3+4i)}{(1-i)} = \dfrac{(3+4i)(1+i)}{(1-i)(1+i)}\)M1 Multiply top and bottom by \((1+i)\)
\(= \dfrac{(3+4i)(1+i)}{2}\)A1 \((1+i)(1-i) = 2\)
\(= -\dfrac{1}{2} + \dfrac{7}{2}i\)A1 or \(\dfrac{-1+7i}{2}\)
Special case: \(\dfrac{z_1}{z_2} = \dfrac{(1-i)}{(3+4i)} = \dfrac{(1-i)(3-4i)}{(3+4i)(3-4i)}\) — Allow M1A0A0
(3)
AnswerMarks
Correct answers only in (b) and (c) scores no marksTotal 7
# Question 1:

## Part (a)

| Answer/Working | Mark | Guidance Notes |
|---|---|---|
| $\arg z_1 = -\arctan(1)$ | M1 | $-\arctan(1)$ or $\arctan(1)$ or $\arctan(-1)$ |
| $= -\dfrac{\pi}{4}$ | A1 | or $-45°$ or awrt $-0.785$ (oe e.g. $\dfrac{7\pi}{4}$) |

**Correct answer only 2/2** | **(2)**

---

## Part (b)

| Answer/Working | Mark | Guidance Notes |
|---|---|---|
| $z_1 z_2 = (1-i)(3+4i) = 3 - 3i + 4i - 4i^2$ | M1 | At least 3 correct terms (unsimplified) |
| $= 7 + i$ | A1 | cao |

**(2)**

---

## Part (c)

| Answer/Working | Mark | Guidance Notes |
|---|---|---|
| $\dfrac{z_2}{z_1} = \dfrac{(3+4i)}{(1-i)} = \dfrac{(3+4i)(1+i)}{(1-i)(1+i)}$ | M1 | Multiply top and bottom by $(1+i)$ |
| $= \dfrac{(3+4i)(1+i)}{2}$ | A1 | $(1+i)(1-i) = 2$ |
| $= -\dfrac{1}{2} + \dfrac{7}{2}i$ | A1 | or $\dfrac{-1+7i}{2}$ |

**Special case:** $\dfrac{z_1}{z_2} = \dfrac{(1-i)}{(3+4i)} = \dfrac{(1-i)(3-4i)}{(3+4i)(3-4i)}$ — Allow M1A0A0

**(3)**

**Correct answers only in (b) and (c) scores no marks** | **Total 7**
\begin{enumerate}
  \item Given that $z _ { 1 } = 1 - \mathrm { i }$,\\
(a) find $\arg \left( z _ { 1 } \right)$.
\end{enumerate}

Given also that $z _ { 2 } = 3 + 4 \mathrm { i }$, find, in the form $a + \mathrm { i } b , a , b \in \mathbb { R }$,\\
(b) $z _ { 1 } z _ { 2 }$,\\
(c) $\frac { z _ { 2 } } { z _ { 1 } }$.

In part (b) and part (c) you must show all your working clearly.\\

\hfill \mbox{\textit{Edexcel FP1 2012 Q1 [7]}}