Given that \(f(r) = \frac{1}{4r-1}\), show that
$$f(r) - f(r+1) = \frac{A}{(4r-1)(4r+3)}$$
where \(A\) is an integer. [2 marks]
Use the method of differences to find the value of \(\sum_{r=1}^{50} \frac{1}{(4r-1)(4r+3)}\), giving your answer as a fraction in its simplest form. [4 marks]
Find the modulus of the complex number \(-4\sqrt{3} + 4\mathrm{i}\), giving your answer as an integer. [2 marks]
The locus of points, \(L\), satisfies the equation \(|z + 4\sqrt{3} - 4\mathrm{i}| = 4\).
Sketch the locus \(L\) on the Argand diagram below. [3 marks]
The complex number \(w\) lies on \(L\) so that \(-\pi < \arg w \leq \pi\).
Find the least possible value of \(\arg w\), giving your answer in terms of \(\pi\). [2 marks]
Solve the equation \(z^3 = -4\sqrt{3} + 4\mathrm{i}\), giving your answers in the form \(re^{\mathrm{i}\theta}\), where \(r > 0\) and \(-\pi < \theta \leq \pi\). [5 marks]
Given that \(y = \sinh x\), use the definition of \(\sinh x\) in terms of \(e^x\) and \(e^{-x}\) to show that
$$x = \ln(y + \sqrt{y^2 + 1}).$$ [4 marks]
A curve has equation \(y = 6\cosh^2 x + 5\sinh x\).
Show that the curve has a single stationary point and find its \(x\)-coordinate, giving your answer in the form \(\ln p\), where \(p\) is a rational number. [5 marks]
The curve lies entirely above the \(x\)-axis. The region bounded by the curve, the coordinate axes and the line \(x = \cosh^{-1} 2\) has area \(A\).
Show that
$$A = a\cosh^{-1} 2 + b\sqrt{3} + c$$
where \(a\), \(b\) and \(c\) are integers. [5 marks]
By applying de Moivre's theorem to \((\cos \theta + \mathrm{i} \sin \theta)^4\), where \(\cos \theta \neq 0\), show that
$$(1 + \mathrm{i} \tan \theta)^4 + (1 - \mathrm{i} \tan \theta)^4 = \frac{2\cos 4\theta}{\cos^4 \theta}$$ [3 marks]
Hence show that \(z = \mathrm{i} \tan \frac{\pi}{8}\) satisfies the equation \((1 + z)^4 + (1 - z)^4 = 0\), and express the three other roots of this equation in the form \(\mathrm{i} \tan \phi\), where \(0 < \phi < \pi\). [2 marks]
Use the results from part (b) to find the values of: