Volume of revolution with parts

A question is this type if and only if it requires finding a volume of revolution where the integral for the volume necessitates integration by parts.

3 questions · Standard +0.5

1.08i Integration by parts4.08d Volumes of revolution: about x and y axes
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AQA C3 2012 June Q4
7 marks Standard +0.3
4
  1. By using integration by parts, find \(\int x \mathrm { e } ^ { 6 x } \mathrm {~d} x\).
    (4 marks)
  2. The diagram shows part of the curve with equation \(y = \sqrt { x } \mathrm { e } ^ { 3 x }\). \includegraphics[max width=\textwidth, alt={}, center]{d3c66c34-b09c-4223-8383-cf0a68419bf9-4_547_846_536_591} The shaded region \(R\) is bounded by the curve \(y = \sqrt { x } \mathrm { e } ^ { 3 x }\), the line \(x = 1\) and the \(x\)-axis from \(x = 0\) to \(x = 1\). Find the volume of the solid generated when the region \(R\) is rotated through \(360 ^ { \circ }\) about the \(x\)-axis, giving your answer in the form \(\pi \left( p \mathrm { e } ^ { 6 } + q \right)\), where \(p\) and \(q\) are rational numbers.
    (3 marks)
AQA C3 2014 June Q6
9 marks Standard +0.8
6
  1. By using integration by parts twice, find $$\int x ^ { 2 } \sin 2 x d x$$
  2. A curve has equation \(y = x \sqrt { \sin 2 x }\), for \(0 \leqslant x \leqslant \frac { \pi } { 2 }\). The region bounded by the curve and the \(x\)-axis is rotated through \(2 \pi\) radians about the \(x\)-axis to generate a solid. Find the exact value of the volume of the solid generated.
    [0pt] [3 marks]
AQA C3 2011 June Q9
11 marks Standard +0.3
  1. Use integration by parts to find \(\int x\ln x \, dx\). [3]
  2. Given that \(y = (\ln x)^2\), find \(\frac{dy}{dx}\). [2]
  3. The diagram shows part of the curve with equation \(y = \sqrt{x\ln x}\). \includegraphics{figure_9} The shaded region \(R\) is bounded by the curve \(y = \sqrt{x\ln x}\), the line \(x = e\) and the \(x\)-axis from \(x = 1\) to \(x = e\). Find the volume of the solid generated when the region \(R\) is rotated through 360° about the \(x\)-axis, giving your answer in an exact form. [6]